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Alecsey [184]
2 years ago
8

help plssss (I’ll give 80 pointsss)

Mathematics
2 answers:
Anna71 [15]2 years ago
6 0

Answer:

here in the figure

5 +2 = 7

so the vertical lines is in the points 5 and 7 .

if you want to find

you need to add both points 5 and 2

so after adding both you will get answer 7

hope it is helpful to you️☺️☺️☺️☺️☺️☺️☺️

Fed [463]2 years ago
5 0

Answer:

5 + 2 = 7

Step-by-step explanation:

The vertical lines are on the points 5 and 7. So to get from five to seven you move two to the right

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This is for a friend and don't use the 2 answers until she is done mmmk, I think I made myself clear.
AlladinOne [14]

Answer:

no because 2+2=4

Step-by-step explanation:

3 0
2 years ago
It takes Fred 32 minutes to type and spell check 5 pages of a manuscript. Find how long it takes
sveta [45]

Answer:

26

Step-by-step explanation:

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6 0
2 years ago
What is the value of -8 (17-12) over -2(8-(-2))<br><br> A. -4<br> B. -2<br> C. 2 <br> D. 4
Ivan

Answer:

C=2

Step-by-step explanation:

-8(17-12)= -8(5)= -40

then

-2(8-(-2))= -2(10) = -20

so then

-40/-20

=-2

3 0
3 years ago
Read 2 more answers
function f of x is a straight line which joins the ordered pairs negative 2.8, 16.4 and 3.5, negative 2.5. Function g of x is a
Alecsey [184]
Given the graph of the function
f(x)=-3x+8
and the graph of the function
g(x)=(0.25)^x

-3x+8=(0.25)^x when f(x) = g(x).
This occurs at the point(s) of intersection of the graphs of the function f(x) and g(x).

From the graph, we can approximate the points of intersection of the graphs of the function f(x) and g(x) to pe points (-1.9, 13.7) and (2.7, 0).
5 0
3 years ago
Derivative of<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20-%202x%20-%201%20%7D%7B%20%7Bx%7D%5E%7B2
Anastaziya [24]

Answer:

\displaystyle  \frac{dy}{dx} =    \frac{2x + 2}{x^3}

Step-by-step explanation:

we would like to figure out the derivative of the following:

\displaystyle  \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }

to do so, let,

\displaystyle y =  \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }

By simplifying we acquire:

\displaystyle y =  3 -  \frac{2}{x}  -  \frac{1}{ {x}^{2} }

use law of exponent which yields:

\displaystyle y =  3 -  2 {x}^{ - 1}  -   { {x}^{  - 2} }

take derivative in both sides:

\displaystyle  \frac{dy}{dx} =  \frac{d}{dx}  (3 -  2 {x}^{ - 1}  -   { {x}^{  - 2} } )

use sum derivation rule which yields:

\rm\displaystyle  \frac{dy}{dx} =  \frac{d}{dx}  3 -   \frac{d}{dx} 2 {x}^{ - 1}  -     \frac{d}{dx} {x}^{  - 2}

By constant derivation we acquire:

\rm\displaystyle  \frac{dy}{dx} =  0 -   \frac{d}{dx} 2 {x}^{ - 1}  -     \frac{d}{dx} {x}^{  - 2}

use exponent rule of derivation which yields:

\rm\displaystyle  \frac{dy}{dx} =  0 -   ( - 2 {x}^{ - 1 -1} ) -     ( - 2 {x}^{  - 2 - 1} )

simplify exponent:

\rm\displaystyle  \frac{dy}{dx} =  0 -   ( - 2 {x}^{ -2} ) -     ( - 2 {x}^{  - 3} )

two negatives make positive so,

\displaystyle  \frac{dy}{dx} =   2 {x}^{ -2} +      2 {x}^{  - 3}

<h3>further simplification if needed:</h3>

by law of exponent we acquire:

\displaystyle  \frac{dy}{dx} =   \frac{2 }{x^2}+       \frac{2}{x^3}

simplify addition:

\displaystyle  \frac{dy}{dx} =    \frac{2x + 2}{x^3}

and we are done!

5 0
3 years ago
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