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3 years ago

Solve for x:

class="latex-formula">

Mathematics

2 answers:

iVinArrow [24]3 years ago

8 0

Answer:

x = 4/(11y)

Step-by-step explanation:

22yx = 8

Solve for x so divide each side by 22y

22xy/22y = 8/22y

x = 4/(11y)

Inessa [10]3 years ago

8 0

The answer is x=4/(y)

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kicyunya [14]

For both of these, we will divide the wanted outcome by the number of possible outcomes. We will end up with a decimal. A decimal multiplied by 100 becomes a percent.

[a] 50%

$\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{\text{student failed}}{\text{Period 2's class}} =\frac{12}{24} =0.5,\:0.5*100=50\%$

[b] 52%

$\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{\text{student failed from Period 3}}{\text{fails from both classes}} =\frac{13}{25} =0.52,$

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1 year ago

Help me please and thank you

fiasKO [112]

Answer:

$51.70

Step-by-step explanation:

I don't know how to explain it actually so I am just going to do this...

y= 0.1(x + 20) +7

y=0.1x + 2 + 7

y=0.1x +9

y=0.1(427)+9

y=42.7+9

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So, maybe the answer is $51.70.

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2 years ago

Walter walked 15.5 blocks from his house to work. It took him 35 minutes. What is his rate in blocks per hour?

Naddik [55]

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2 years ago

In a telephone poll, 4 people said that they liked shopping and 10 people said that they don’t like shopping. What is the ratio

Effectus [21]

Answer:

4:10 in simplest form 2:5

Step-by-step explanation:

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6 0

2 years ago

Read 2 more answers

Find the? inverse, if it? exists, for the given matrix.<br><br> [4 3]<br><br> [3 6]

True [87]

Answer:

Therefore, the inverse of given matrix is

$=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}$

Step-by-step explanation:

The inverse of a square matrix $A$ is $A^{-1}$ such that

$A A^{-1}=I$ where I is the identity matrix.

Consider, $A = \left[\begin{array}{ccc}4&3\\3&6\end{array}\right]$

$\mathrm{Matrix\:can\:only\:be\:inverted\:if\:it\:is\:non-singular,\:that\:is:}$

$\det \begin{pmatrix}4&3 \\3&6\end{pmatrix}\ne 0$

$\mathrm{Find\:2x2\:matrix\:inverse\:according\:to\:the\:formula}:\quad \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}^{-1}=\frac{1}{\det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}}\begin{pmatrix}d\:&\:-b\:\\ -c\:&\:a\:\end{pmatrix}$

$=\frac{1}{\det \begin{pmatrix}4&3\\ 3&6\end{pmatrix}}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}$

$\mathrm{Find\:the\:matrix\:determinant\:according\:to\:formula}:\quad \det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}\:=\:ad-bc$

$4\cdot \:6-3\cdot \:3=15$

$=\frac{1}{15}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}$

$=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}$

Therefore, the inverse of given matrix is

$=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}$

4 0

3 years ago