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Vesna [10]
3 years ago
11

Please help! Will give brainliest!

Mathematics
2 answers:
tatyana61 [14]3 years ago
8 0

Answer:

\frac{5}{12} =\frac{2}{x}

Step-by-step explanation:

EF and JK are similar, and the other side we know, FG, is similar to KL. From there, just put them into a ratio!

\frac{EF}{JK} =\frac{FG}{KL}

\frac{5}{12} =\frac{2}{x}


muminat3 years ago
3 0

Answer:

5                 2

-------- = -------------

12                  x

Step-by-step explanation:

We need to take the ratio of the sides in the same order.  Length over length

EF                 FG

-------- = -------------

JK                 KL


5                 2

-------- = -------------

12                  x

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alexdok [17]

Answer:

646.39

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8 0
2 years ago
Help me please ASAP
Lina20 [59]

Answer:

m<2 = 70degrees

m<3 = 70degrees

m<4 = 110degrees

m<5 = 110degrees

m<6 = 70degrees

m<7 = 70degrees

m<8 = 110degrees

Step-by-step explanation:

A line has the angles of 180 degrees so if m<1 is 110 then m<2 must be 70degrees. Then m<4 is opposite side of m<1 so it has to be the same number of degrees and the same for m<3 is the opposite side of m<2.

You repeat the process with 5678

7 0
3 years ago
Barney ate 21 M&amp;M's. If he ate 15% of the bag of M&amp;M's, how many were in the bag to start?
natali 33 [55]

Answer:

3.15

i just used the calculater :)

8 0
2 years ago
Read 2 more answers
Axis of sym: x =
marta [7]

Answer:

<h2>SEE BELOW</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • quadratic function
  • PEMDAS
<h3>let's solve:</h3>

vertex:(h,k)

therefore

vertex:(-1,4)

axis of symmetry:x=h

therefore

axis of symmetry:x=-1

  • to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0

vertex form of quadratic equation:

  • y=a(x-h)²+k

therefore

  • y=a(x-(-1))²+4
  • y=a(x+1)²+4

it's to notice that we don't know what a is

therefore we have to figure it out

the graph crosses y-asix at (0,3) coordinates

so,

3=a(0+1)²+4

simplify parentheses:

3 = a(1 {)}^{2}  + 4

simplify exponent:

3 =  a + 4

therefore

a =  - 1

our vertex form of quadratic equation is

  • y=-(x+1)²+4

let's simplify it to standard form

simplify square:

y =  - ( {x}^{2}  + 2x + 1)  + 4

simplify parentheses:

y =  -  {x}^{2}  - 2x - 1 + 4

simplify addition:

y =  -  {x}^{2}  - 2x + 3

therefore our answer is D)y=-x²-2x+3

the domain of the function

x\in \mathbb{R}

and the range of the function is

y\leqslant 4

zeroes of the function:

-  {x}^{2}  - 2x + 3 = 0

\sf divide \: both \: sides \: by \:  - 1

{x}^{2}  + 2x - 3 = 0

\implies \:  {x}^{2} +   3x  - x  +  3 = 0

factor out x and -1 respectively:

\sf \implies \: x(x + 3)   - 1(x  + 3 )= 0

group:

\implies \: (x - 1)(x + 3) = 0

therefore

\begin{cases} x_{1} = 1 \\  x_{2}  =  - 3\end{cases}

4 0
3 years ago
What is the solution of the equation (y – 6) = 2y - 3?
schepotkina [342]

Answer:

y=-3

Step-by-step explanation:

7 0
2 years ago
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