Answer:
<B = 47°
<C = 28°
b = AC = 28.0
Step-by-step explanation:
Given:
∆ABC
AB = c = 18
BC = a = 37
<A = 105°
Required:
Length of AC = b
measure of angle B and angle C
SOLUTION:
==>Use the sine rule, sin A/a = sinC/c to find the angle of C:
SinA = sin(105) = 0.9659
a = 37
sinC = ?
c = 18
0.9659/37 = sinC/18
Cross multiply
0.9659*18 = 37*sinC
17.3862 = 37*sinC
Divide both sides by 37
17.3862/37 = sinC
0.4699 = sinC
sinC = 0.4699
C = Sin-¹(0.4699)
C = 28.0° (nearest tenth)
==>Find angle B using sum of angles in a triangle:
Angle B = 180 - (105+28)
Angle B = 180 - 133
Angle B = 47°
==>Find length of b using sine rule, b/sinB = c/sinC:
SinC = sin(28) = 0.4695
SinB = sin(47) = 0.7314
c = 18
b = ?
b/0.7314 = 18/0.4695
Cross multiply
b*0.4695 = 18*0.7314
b*0.4695 = 13.1652
Divide both sides by 0.4695
b = 13.1652/0.4695
b = 28.0 (nearest tenth)
First we find the area of the two triangles on each side (keep in mind that they are equal/congruent to each other):
(24*10)/2 = 120 cm^2
Then you find the areas of the three rectangles that are left:
24*19 = 456 cm^2
26*19 = 494 cm^2
10*19 = 190 cm^2
Finally, to find the surface area of the prism:
120+120+456+494+190 = 1,380 cm^2
Yes it's A cos that's the correct answer
Answer:
angle YUT = 120
Step-by-step explanation:
in Triangle SUT
angle 70 + angle 50 + angle x = 180
70 + 50 + x = 180
120 + x = 180
x = 180 - 120
x = 60
angle SUT = 60
angle SUT + angle YUT = 180 ( straight line)
60 + x = 180
x = 120
Therefore angle YUT ( exterior angle ) = 120
Answer:
Inter-quartile range
Step-by-step explanation:
When you have the quartile, you can use the IQR (interquartile range) to measure the dispersion.
IQR = Q3 - Q1
Movies: IQR = 195 - 162 = 33
Basketball: IQR = 225 - 170 = 55
Attendance at Basketball is more dispersed/spread out as compared to attendance at Movies
