D. y=5x+6 and 2y-12-10x=0 has infinitely many solutions and both lines are linear
E. y=4x+1, y=9x+4 has the solutions x = -3/5, y = -7/5
So you would do
5×4×3= 60
and
5×4=20
so, for a 3 digit code there are 60 possibilities and for a 2 digit code there are 20 possibilities.
From the given figure ,
RECA is a quadrilateral
RC divides it into two parts
From the triangles , ∆REC and ∆RAC
RE = RA (Given)
angle CRE = angle CRA (Given)
RC = RC (Common side)
Therefore, ∆REC is Congruent to ∆RAC
∆REC =~ ∆RAC by SAS Property
⇛CE = CA (Congruent parts in a congruent triangles)
Hence , Proved
<em>Additional</em><em> comment</em><em>:</em><em>-</em>
SAS property:-
"The two sides and included angle of one triangle are equal to the two sides and included angle then the two triangles are Congruent and this property is called SAS Property (Side -Angle-Side)
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Consider the proof. Given: Segment AB is parallel to line DE. Prove: AD/DC = BE/EC What is the missing statement in Step 5? A.) AC = BC B.) AC/DC = BC/EC C.) AD...
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Answer:
If the x-6 is all under the sqrt, the last answer is right:
6<= x <= infinity
If only x is under the sqrt and - 6 is NOT under the sqrt, then:
0 <= x <= infinity is the correct answer.
Step-by-step explanation:
You can look at the equation and or graph to determine the domain of a function. The domain is all the x's that may go into the equation or all the x's on the graph of the function. Inside of a squareroot symbol the number inside there must be positive. While considering the equation, only x's that keep that inside positive can be used.
For sqrt(x-6), x has to be 6 or bigger.
For sqrt(x) - 6, x has to be 0 or bigger.