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kompoz [17]
3 years ago
5

What is the value of m in the equation 1/2m-3/4n when n = 8?

Mathematics
1 answer:
kirill [66]3 years ago
3 0

Answer:

-\frac{1}{32}

Step-by-step explanation:

n = 8\\1/2(8) - 3/4(8) = 1/16-3/32

Multiply the numerator and denomiator of 1/16 by 2 so that the denominators are equal and we can subtract.

\frac{1}{16} *\frac{2}{2} =\frac{2}{32}

Then, subtract

\frac{2}{32} -\frac{3}{32} = \frac{2-3}{32} =- \frac{1}{32}

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En una muestra de 50 restaurantes de comida rápida, la venta media fue de $3.000, y la desviación estándar, $200. El intervalo d
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Respuesta:

(2945.411; 3054.589)

Explicación paso a paso:

Dado ;

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Desviación estándar, s = 200

Nivel de confianza, Zcrítico al 95% = 1,96

El intervalo de confianza se define como:

Xbar ± margen de error

Margen de error = Zcrítico * s / sqrt (n)

Margen de error = 1,96 * 200 / sqrt (50)

Margen de error = 54.589

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Límite superior = (3000 + 54.589) = 3054.589

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8 0
3 years ago
Assume that I=E/(R+r) prove that 1/I=R/E+r/E ?​
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