All categories

3 years ago

What is the LATERAL surface area of the rectangular pyramid below???

Mathematics

2 answers:

kherson [118]3 years ago

5 0

684 ft²

Area of rectangle :-

A = 18 ft * 20ft

A = 360 ft²

Area of 2 triangles :-

A = 2 * 8ft * 18 ft * 1/2

A = 144 ft²

Area of 2 triangles :-

A = 2 * 1/2 * 9ft * 20ft

A = 180 ft²

Total Area :-

A = ( 360 + 144 + 180 ) ft²

A = 684 ft²

emmasim [6.3K]3 years ago

4 0

Answer:

684 sq.ft

Step-by-step explanation:

(1) The base area of the pyramid is 18x20=360 sq.ft

(2) The Triangles of the pyramid:

1. There are two kinds of the triangles.

2. Smaller one: 18x8/2 (base times height divide 2)=72 sq.ft

3. Bigger one: 20x9/2=90 sq.ft

4. There are two of them so 72+72+90+90=324 sq.ft

And so 360+324=684 sq.ft.

You might be interested in

Billy jogs 4/5 kilometers every minute how many kilometers does he jog after 6 1/8 minutes

finlep [7]

Answer:

He jogs 4 9/10 kilometers in 6 1/8 minutes

Step-by-step explanation:

If you multiple 4/5 time 6 1/8 you'll get 4.9, which in fraction form is 4 9/10.

6 0

3 years ago

Ruben adds some water to a glass of juice. The ratio of water to juice in his glass in now 4:6. Which fraction below represents

Anarel [89]

Answer:

C. 2/3

Step-by-step explanation:

4/6 is equivalent to 2/3 (divide by 2)

5 0

3 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

3 years ago

The ratio of yellow shirts to green shirts in Ms. Grayson’s closet is 5:2. She has a total of 21 yellow and green shirts combine

VikaD [51]

15 yellow 6 green
5+2 equals 7
21 divided by 3 is 7
5x3=15
2x3=6

6 0

3 years ago

ASAP I NEED HELP NOWW

marshall27 [118]

27 x 1.25= 33.75

5 x 1.99=9.95

1 x 1.50= 1.50

add that up =45.2

/26 students = 1.73 dollars

4 0

3 years ago

Read 2 more answers