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lutik1710 [3]
3 years ago
14

1/2 as long as 6 meters

Mathematics
1 answer:
IrinaVladis [17]3 years ago
5 0

Answer:

Let the total length be x

Now 1/2 • x = 6

=> x = 6•2

=> x = 12

.°. The value of x = 12

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What's the area of the trapezoid
BlackZzzverrR [31]
46.5cm squared I believe
Hope this helped ;)

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4 years ago
A rectangular garden is divided into two sections as shown.
azamat

Step-by-step explanation:

Pythagoras (for right-angled triangles) :

c² = a² + b²

c being the Hypotenuse, the side opposite of the right angle. and that would be here the diagonal.

c = diagonal = 10 ft

therefore, the width of the rectangle is 10/2 = 5 ft

10² = 5² + b²

100 = 25 + b²

b² = 75

b = length = sqrt(75) = 8.660254038... ft

8 0
2 years ago
Solve for f. <br> 6f + 9g = 3g + f
Mashcka [7]

Answer:

f=-6g/5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A cake recipe requires 2/3 of an ounce of baking powder. How many cakes can be made from a package containing 50 ounces of bakin
AnnZ [28]

Answer:

75

Step-by-step explanation:

Divide 50 by 2/3. Division is the same as asking "how many times can i subtract 2/3 from 59?"

50 \div  \frac{2}{3}

Dividing by a fraction is the same as multiplying by the reciprocal.

50 \times  \frac{3}{2}  = 75

You can subtract 2/3 from 50, 75 times

5 0
3 years ago
There are 16 kids on a soccer team. The players are either boys or girls, and they either prefer playing offense or defense. The
Mariana [72]

Answer:

P(B|A)=\frac{2}{7}

Step-by-step explanation:

The probability of P(B|A) can be read as the probability of event B occurring given event A. In this question, event A occurs when the chosen player is a girl. There are 7 girls on the soccer team. Event B occurs when the chose player plays defense. Since P(B|A) stipulates that event A already occurred, we want the probability of choosing a player who prefers defense from the 7 girls. There are 2 girls who prefer defense, hence P(B|A)=\boxed{\frac{2}{7}}.

<u>Alternative:</u>

For dependent events A and B, the conditional probability of event B occurring given A is given by:

P(B|A)=P(B\cap A)\div P(A)

P(B\cap A) indicates the intersection of P(B) and P(A). In this case, it is the probability that both events occur. Since there are 16 kids on the soccer team and only 2 are girls and prefer defense, P(B\cap A)=\frac{2}{16}=\frac{1}{8}. The probability of event A occurring (chosen player is a girl) is equal to the number of girls (7) divided by the number of kids on the team (16), hence P(A)=\frac{7}{16}.

Therefore, the probability of event B occurring, given event A occurred, is equal to:

P(B|A)=\frac{1}{8}\div \frac{7}{16},\\\\P(B|A)=\frac{1}{8}\cdot \frac{16}{7}=\boxed{\frac{2}{7}}

5 0
3 years ago
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