Answer:
(12x-2 =53 ) (12x=53+2)(12X=55)(x=55/12)X=4.58
Answer:
? = 9.2
Step-by-step explanation:
The angle between a tangent and radius at the point of contact is 90°
Then the triangle shown is right with legs ? , 6.9 and hypotenuse = (6.9 + 4.2) = 11.5
Using Pythagoras' identity in the right triangle
?² + 6.9² = 11.5²
?² + 47.61 = 132.25 ( subtract 47.61 from both sides )
?² = 84.64 ( take the square root of both sides )
? = 
= 9.2
see the attached figure to better understand the problem
we know that
In a parallelogram opposite angles are congruent, and consecutive angles are supplementary
So
in this problem
∠Y=
°
∠W=∠Y
∠W=°
∠Z=∠X
∠Y+∠Z=
°
∠Z=
∠Z=
°
∠X=∠Z
∠X=°
therefore
the answer is
∠Y=°
∠W=°
∠X=°
∠Z=°
9514 1404 393
Answer:
1) f⁻¹(x) = 6 ± 2√(x -1)
3) y = (x +4)² -2
5) y = (x -4)³ -4
Step-by-step explanation:
In general, swap x and y, then solve for y. Quadratics, as in the first problem, do not have an inverse function: the inverse relation is double-valued, unless the domain is restricted. Here, we're just going to consider these to be "solve for ..." problems, without too much concern for domain or range.
__
1) x = f(y)
x = (1/4)(y -6)² +1
4(x -1) = (y-6)² . . . . . . subtract 1, multiply by 4
±2√(x -1) = y -6 . . . . square root
y = 6 ± 2√(x -1) . . . . inverse relation
f⁻¹(x) = 6 ± 2√(x -1) . . . . in functional form
__
3) x = √(y +2) -4
x +4 = √(y +2) . . . . add 4
(x +4)² = y +2 . . . . square both sides
y = (x +4)² -2 . . . . . subtract 2
__
5) x = ∛(y +4) +4
x -4 = ∛(y +4) . . . . . subtract 4
(x -4)³ = y +4 . . . . . cube both sides
y = (x -4)³ -4 . . . . . . subtract 4
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