Volume is equal mass by density
Answer:
a) 45 possible outcomes
b) 55 possible outcomes
Step-by-step explanation:
Given:
- Total cavities = 12
- Selection = 3 parts
- Non-conforming cavities = 2
Find:
a) How many samples contain exactly 1 nonconforming part?
b) How many samples contain at least 1 nonconforming part?
Solution:
- The question asks for the use of combinations to express the outcomes for each scenario.
- For first part, we want the inspector to pick exactly one non-conforming part among 3 selected. So let us say that he has already chosen that one non conforming cavity. Now he has to make 2 more selections out of total conforming cavities = 12 - 2 = 10 conforming cavities. Hence, the total possible outcome is to chose 2 randomly from 10 conforming cavities.
( Exactly 1 ) 10C2 = 45 possible outcomes
- The second part entails that at-least 1 non-conforming cavity is selected. To choose exactly 1 non conforming we calculated above. In the similar way calculate for selecting exactly 2 non-conforming cavities. The total possible outcome would be to choose from 10 conforming and we choose 1 from it:
( Exactly 2 ) 10C1 = 10 possible outcomes
- Hence, for at-least 1 non conforming cavity being selected we same the above two cases calculated:
(At-least 1 ) = ( Exactly 1 ) + ( Exactly 2 )
(At-least 1 ) = 45 + 10 = 55 possible outcomes
It already is a fraction though. I assume you mean to simplify it. You can simplify fraction by taking out the greatest common factor(that they share) in the denominator and numerator. In this case the denominator and numerator share the factor 5. So you if you divide the numerator and denominator by 5 you get 3/10 or the simplest form of the fraction.
The answer is
We have to find the output values for the given input values of the function given as,
Here, x = Input value of the function
And f(x) = Output values
By substituting the input values of x as,
For x = -4,
f(-4) = -4(-4) - 5
= 16 - 5
= 11
For x = 1,
f(1) = -4(1) - 5
= -4 - 5
= -9
For x = 3,
f(4) = -4(3) - 5
= -17
For x = 11,
f(11) = -4(11) - 5
= -44 - 5
= -49
Therefore, Option (A) will represent the output values for the given input values.
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