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3 years ago

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Mathematics

1 answer:

larisa86 [58]3 years ago

7 0

( 3 × 5 ) + ( 2 × 4 ) =

15 + 8 = $ 23

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Serena has $50 to spend. She buys 5 packages of hotdog buns and 5 packages of beef hotdogs. Each package of buns cost $3.85 and

Ne4ueva [31]

Answer:

Serena will have $9.75 left after her purchases.

Step-by-step explanation:

5 packages of buns= 3.85x5= 19.25

5 packages of hotdogs= 4.20x5= 21

19.25+21= 40.25

50-40.25= 9.75

6 0

3 years ago

Read 2 more answers

(PLEASE HELP) <br> Which equation has no solution?

Finger [1]

<h2>Answer: </h2><h2>C, 5/8x + 2.5 = 3/8 x +1.5 + 1/4x</h2><h2>~</h2><h3>There are no values of 'X' that make the equation true, therefore the equation has no solution. </h3><h2>~</h2>

Hope you have a good day, Loves!

Also if I'm right can you let me know, please?

<u>Also Also if I am right can I please have Brainliest??</u>

<em>You don't need to, I'm just glad I could help. ^^</em>

8 0

3 years ago

Read 2 more answers

12 1/3 - ( 2x + 3 2/3)

Citrus2011 [14]

Answer:

hello there the correct answer is 16−2x

Step-by-step explanation:

8 0

2 years ago

If a,b,c,d, and e are non negative such that x^6-289x^4-x^2+289=(x-a)(x+b)(x_c)(x+d)(x^2+ex+1), what is the value of a+b+c+d+e?

Irina18 [472]

Answer:

Step-by-step explanation:

Hello,

If $X=x^2$ it becomes

$X^3-289X^2-X+289=(X^2-1)(X-289)$

and $289=17^2$

$X^2-1=(X-1)(X+1)=(x^2-1)(x^2+1)=(x+1)(x-1)(x^2+1) \\\\x^2-289=x^2-17^2=(x-17)(x+17)$

So,

$x^6-289x^4-x^2+289=(x^2-1)(x^2+1)(x^2-289)=(x-1)(x+1)(x+17)(x-17)(x^2+1)$

a = 1

b = 1

c = 17

d = 17

e = 0

Then a + b + c + d + e = 36

Thanks

3 0

3 years ago

How do I solve this problem??

choli [55]

They're the same like integers.
First you should interpret it.
For example:
a. -3x + 8x is the same like -3 + 8. You just add x.
Which is 5x.

3 0

3 years ago