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3 years ago

6

Mr. Grant spent $8.40 to place an ad in the newspaper. This price included a one-time fee of $6.00 plus $0.08 per word. Which me

thod can be used to determine the total number of words in the ad Mr. Grant placed?

1 answer:

kondaur [170]3 years ago

7 0

Answer:

He used 30 words

Step-by-step explanation:

(8.40 - 6.00) divided by 0.08 = the number of words

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X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

4 0

2 years ago

Which is first X axis or Y axis?

Svetllana [295]

Answer:

You always do the X-axis first. Hope this helps! :)

<h3>CloutAnswers</h3>

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3 years ago

Read 2 more answers

A dog walker charges a flat rate of $6 per walk plus an hourly rate of $30. How much does the dog walkercharge for a 45 minute w

leonid [27]

hello

from the question given, the dog walker charges a flat rate of $6 and an extra $30 per hour.

we can write out an equation in function notation

let the number of hours be represented by x

$f(x)=6+30x$

now we can proceed to solve the cost of the walk for 45 minutes

$\begin{gathered} 1hr=60\min s \\ \text{xhr}=45\min s \\ x=\frac{45}{60} \\ x=\frac{3}{4} \\ \text{therefore 45mins = 3/4 hours} \end{gathered}$

now we can input the value into the equation and know the cost for 45 minutes walk

$\begin{gathered} f(x)=6+30x \\ x=\frac{3}{4} \\ f(x)=6+30(\frac{3}{4}) \\ f(x)=6+22.5 \\ f(x)=28.5 \end{gathered}$

from the calculation above, the cost of 45 minutes walk will cost $28.5

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1 year ago

Question 5 of 8 2 Points Which values are solutions to the inequality below? Check all that apply. x2 > 10

Ket [755]

Answer:

4 and -4

Step-by-step explanation:

> means greater than

x² > 10

4² > 10 → True, 16 is greater than 10

-4² > 10 → True, 16 is greater than 10

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3 years ago

#11 - In the diagram of triangle PST, QR is parallel to ST with PQ = 10 and

Goshia [24]

Answer:

<h2>The length of RT is 3.6 units.</h2>

Step-by-step explanation:

In the image attached, you can observe a representation of the problem.

Notice that we have two parallel lines with two transversal. That means we can use the proportionality theorem to create the following expression

$\frac{PQ}{QS} =\frac{PR}{RT}$

Where $PQ=10$ , $QS=4$ and $PR=9$ .

Replacing all values, and solving for the unknown quantity, we have

$\frac{10}{4}=\frac{9}{x} \\10x=36\\x=\frac{36}{10}\\ x=3.6$

$\therefore RT=3.6$

Therefore, the length of RT is 3.6 units.

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3 years ago