Answer:
1) A line can be defined by two points that are connected by the given line.
We can see that the line r connects the points A and B, then we can call this line as:
AB (the notation usually uses a double arrow in top of the letters)
2) In the image we can see that lines r and s intersect at the point B, then another name for that intersection is: B.
3) 3 colinear points are 3 points that are connected by a single line, an example of this can be the points A, B and C.
4) A plane can be defined by a line and a point outside the line.
For example, we can choose the line AB and the point D, that does not belong to the line.
Then we can call the plane as ABD.
Answer:
Perimeter of rectangle before folded = 56 in
Total area after folding = 156 sq in
Step-by-step explanation:
Rectangle before folded: l = 16 and w = 12
P = 2(16) + 2(12) = 32 + 24 = 56 in.
Figure after folding: Area of trapezoid + area of rectangle
Area of trapezoid = h(
)/2 = 6(4 + 16)/2 = 60
Area of rectangle = lw = 16(6) = 96
Total area after folding = 60 + 96 = 156 sq in.
Note: You could also find the area after folding by substracting the areas of the two triangles in the corners from the area of the original rectangle. Your choice. OK?
I think is you just need to multiply that input number just to get the right answers
Example: 5 multiply by 5 equal 25
Try it
9514 1404 393
Answer:
64k^6 -64k^5 +(80/3)k^4 -(160/27)k^3 +(20/27)k^2 -(4/81)k +1/729
Step-by-step explanation:
The row of Pascal's triangle we need for a 6th power expansion is ...
1, 6, 15, 20, 15, 6, 1
These are the coefficients of the products (a^(n-k))(b^k) in the expansion of (a+b)^n as k ranges from 0 to n.
Your expansion is ...
1(2k)^6(-1/3)^0 +6(2k)^5(-1/3)^1 +15(2k)^4(-1/3)^2 +20(2k)^3(-1/3)^3 +...
15(2k)^2(-1/3)^4 +6(2k)^1(-1/3)^5 +1(2k)^0(-1/3)^6
= 64k^6 -64k^5 +(80/3)k^4 -(160/27)k^3 +(20/27)k^2 -(4/81)k +1/729
