4c + 4t + 3s = total number of legs
example : Lets say u have 3 chairs (c) and 2 tables (t) and 4 stools (s)...
4c + 4t + 3s =
4(3) + 4(2) + 3(4) =
12 + 8 + 12 = 32 legs...then u would have 32 legs
Answer:
The correct option for this is C.) The mean and median age are more likely to be the same for the students in Math 1.
Step-by-step explanation:
i) The median age of the students is Math 1 is less than the median age of the students in Math 2.
This statement is NOT TRUE as the median age of students in Math 1 = median age of students in Math 2 = 19
ii) The mean and median age are most likely the same for both sets of data.
This statement is NOT TRUE. The mean age of students in Math 2 should be greater than mean age of students in Math 1.
iii) The mean and median age are more likely to be the same for the students in Math 1.
This statement is TRUE.
This problem can be solved with simple subtraction. 150.25 minus 78 will give you the answer you need. (72.25 yards of rope)
The number rounded to the nearest tenth is 54 degrees
I am not sure if this answers your question exactly, but because both equations are equal to "u" than you can equal them to each other.
It would be the last answer because you are setting them equal to each other.
