Answer:
ex:Speed (S) is the ratio of the distance (D) covered to the time (t) taken.
That is, S = D/t
Suppose Andrew ran a distance D1 in 1 hour (3600 seconds) at a Speed, say S1, we have
S1 = D1/t
We can then say he ran a distance
D1 = t × S1
= 3600S1
Similarly, let's say Karleigh ran a distance
D2 = t × S2
= 3600S2
Let us compare these two, you will notice that the bigger number between S1 and S2 is going to determine the bigger number between D1 and D2.
Let's choose random numbers for S1 and S2 for clarity, say S1 = 5, S2 = 10
D1 = 3600 × 5
= 18000
D2 = 3600 × 10
= 36000
This makes D2 bigger than D1. this is an example i found on the internet.
Step-by-
hope this helps, good luck
Answer:
Step-by-step explanation:
−189=4x−3(−4x+15)
−189=16x−45
16x−45=−189
16x−45+45=−189+45
16x=−144
16x
/16
=
−144
/16
x=−9
Good luck honey !!
Answer:
5 miles
Step-by-step explanation:
distance = speed · time
Tom's distance = (50 mi/h)·(2.5 h) = 125 mi
Albert's distance = (65 mi/h)·(2 h) = 130 mi
Albert drove 130 -125 = 5 miles farther than Tom.
Answer:
Angle a = 80°, Angle b = 55°, Angle c = 45°, Angle d = 80°
Step-by-step explanation:
To find the measure of Angle a, we add 55 and 45, then subtract the sum from 180.
180 - 100 = 80
Angle a is 80°.
Then, we solve for Angle b. Line segment CD is congruent to Line AB, so Angle b is congruent to 55°.
After that, we find Angle c. Line segment AC is congruent to Line segment BD, so Angle c is congruent to 45°.
Lastly, we solve for Angle d using the same method we used for Angle b and Angle c. Angle d is congruent to Angle a, so it measures 80°.
So, Angle a = 80°, Angle b = 55°, Angle c = 45°, Angle d = 80°.
