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CaHeK987 [17]
2 years ago
15

I have a hard time understanding this question​

Mathematics
1 answer:
Alex73 [517]2 years ago
8 0

Answer:

22m+42 is the answer

Step-by-step explanation:

All you have to do is simplify and add the common factors.

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Question 9: Please help, what would be the length of the image of the segment GH?
shepuryov [24]

Answer:

<u><em></em></u>

  • <u><em>The length of the image of the segment GH would be 5 units.</em></u>

Explanation:

You can use the <em>center of dilation</em> as your origin of coordintes.

Thus, the <em>point H</em> would have coordinates (0,0) and the <em>point G</em> (-1,0).

A <em>dilation</em> multiplies the coordinates by the <em>scale factor</em>. Hence:

  • H = (0,0) → H' = 5 × (0,0) = (0,0)
  • G = (-1,0) → G] = 5 × (-1, 0) = (-5, 0)

Thus, the length of the image of segment GH would be the distance from 0 to -5 in a number line, which is 5.

3 0
2 years ago
Read 2 more answers
What is the value of x-6
Arlecino [84]
3x - 8 = -2    |subtract 10 from both sides

3x - 18 = -12    |divide both sides by 3

x - 6 = -4
7 0
3 years ago
What is the quotient 2y^-6y-20/4y+12 ÷ y+5y+6/3y^2+28y+27​
malfutka [58]

Answer with explanation:

 \rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}

→y²+5y+6

=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

=(y+2)(y+3)

→y² -3 y-10

=y² -5 y+2 y -10

=y×(y-5)+2×(y-5)

=(y+2)(y-5)

6 0
3 years ago
Read 2 more answers
Which statement is TRUE?
Anastaziya [24]

Answer:

the answer is C i think

Step-by-step explanation:

6 0
3 years ago
I am not sure on how to do this ​
sweet [91]

Answer:

CP = 8 cm

Step-by-step explanation:

Given two chords that intersect inside a circle, then then the product of the parts of one chord is equal to the product of the parts of the other chord, that is

DP × CP = AP × PB ← substitute values

6 × CP = 12 × 4

6CP = 48 ( divide both sides by 6 )

CP = 8

8 0
2 years ago
Read 2 more answers
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