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3 years ago

Compare the two box plots below. Which would have a larger IQR?

Mathematics

1 answer:

Alecsey [184]3 years ago

8 0

Answer:

Varsity has a larger IQR

Step-by-step explanation:

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Solve -(1+7g)-6(-7-g)=36

maria [59]

Eliminate parentheses using the distributive property.

... -1 -7g +42 +6g = 36

... 41 -g = 36 . . . . collect terms

... 41 -36 = g . . . . add g-36 to both sides

... 5 = g . . . . . .. . . your answer

6 0

3 years ago

Factorise 18u²-50y completely.

Rufina [12.5K]

Answer:

$2(3u + 5 \sqrt{y} )(3u - 5 \sqrt{y} )$

Step-by-step explanation:

$18 {u}^{2} - 50y \\ \\ = 2[9 {u}^{2} - 25y] \\ \\ = 2[(3 {u})^{2} - (5 \sqrt{y} )^{2} ] \\ \\ = 2(3u + 5 \sqrt{y} )(3u - 5 \sqrt{y} )$

6 0

3 years ago

Need help pleaseI was bad at math in school so lwant to learn

aleksklad [387]

The probability of an event is expressed as

$Pr(\text{event) =}\frac{Total\text{ number of favourable/desired outcome}}{Tota\text{l number of possible outcome}}$

Given:

$\begin{gathered} \text{Red}\Rightarrow2 \\ \text{Green}\Rightarrow3 \\ \text{Blue}\Rightarrow2 \\ \Rightarrow Total\text{ number of balls = 2+3+2=7 balls} \end{gathered}$

The probability of drwing two blue balls one after the other is expressed as

$Pr(\text{blue)}\times Pr(blue)$

For the first draw:

$\begin{gathered} Pr(\text{blue) = }\frac{number\text{ of blue balls}}{total\text{ number of balls}} \\ =\frac{2}{7} \end{gathered}$

For the second draw, we have only 1 blue ball left out of a total of 6 balls (since a blue ball with drawn earlier).

Thus,

$\begin{gathered} Pr(\text{blue)}=\frac{number\text{ of blue balls left}}{total\text{ number of balls left}} \\ =\frac{1}{6} \end{gathered}$

The probability of drawing two blue balls one after the other is evaluted as

$\begin{gathered} \frac{1}{6}\times\frac{2}{7} \\ =\frac{1}{21} \end{gathered}$

The probablity that none of the balls drawn is blue is evaluted as

$\begin{gathered} 1-\frac{1}{21} \\ =\frac{20}{21} \end{gathered}$

Hence, the probablity that none of the balls drawn is blue is evaluted as

$\frac{20}{21}$

8 0

1 year ago

5m+72=−2m+52 A -1 B -1/7 C 6/7 D 7

shtirl [24]

<span>First we add 2m to both sides, leaving 7m + 72 = 52 (since -2m + 2m cancels out). Next, we subtract 72 from both sides, bringing us to 7m = -20. Solving for m, we get -20/7. Since this is not one of the listed options, it is possible that the original poster has made a typographical error.</span>

5 0

3 years ago

4x^2+8x-12 it needs to be factored :)

Arlecino [84]

Answer:4((x+3)(x-1))

Step-by-step explanation:

Factorize the common terms

4(x^2+2x-3)

Factorize

X^2+2x-3=(x+3)(x-1)

(X+3)(x-1)

4((x+3)(x-1))

3 0

3 years ago