Answer:
No solutions
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Answer:
x = 1\2 and y = 0
Step-by-step explanation:
8x + 3y = 4 * 5\3
14x - 5y = 7 * 1
40\3x + 5y = 20\3 -------- 1
14x - 5y = 7 ----------------- 2
add equation 1 and 2
82\3x = 41\3
x = <u>4</u><u>1</u><u> </u> <u>3</u>
3 * 82
x = 1\2
subtitute 1\2 for x in equation 2
14\2 - 5y = 7
7 - 5y = 7
5y = 7 - 7
y = 0\5
y = 0
thus x = 1\2 and y = 0
Answer:
Step-by-step explanation:
Solution by substitution method
3x-4y=8
and 18x-5y=10
Suppose,
3x-4y=8→(1)
and 18x-5y=10→(2)
Taking equation (1), we have
3x-4y=8
⇒3x=4y+8
⇒x=(
4y+8)/
3 →(3)
Putting x=
(4y+8
)/3 in equation (2), we get
18x-5y=10
18(
(4y+8)
/3) -5y=10
⇒24y+48-5y=10
⇒19y+48=10
⇒19y=10-48
⇒19y= -38
⇒y=-
38
/19
⇒y= -2→(4)
Now, Putting y=-2 in equation (3), we get
x=4y+8
x=
(4(-2)+8)
/3
⇒x=
(-8+8)/
3
⇒x=
0/
3
⇒x=0
∴x=0 and y= -2
Answer:log (20/5)
Step-by-step explanation:
When subtracting logs you divide the numbers after the log
