A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
1 is 0.0012. 2 is 3.25 and 3 is 3.25
Answer:
X = 21/4 - 7/4 = 14/4 = 7/2 = 3 and 1/2
Step-by-step explanation:
X + (2 and 1/2) - 3/4 = 5 and 1/4
X + 2 and 2/4 - 3/4 = 5 and 1/4 <--- common denominator
X + 10/4 - 3/4 = 21/4
X + 7/4 = 21/4
X = 21/4 - 7/4 = 14/4 = 7/2 = 3 and 1/2
($94.11 + $52.75) + (-$25.20 + -$22.04 + -$8.50) =
($146. 86) - (-$55.74) =
$94.12
$94.12 is the account balance at the end of the month.
The second Version of the game is greater for hitting the down button because substituting any number for x, the second equation would always end up having a greater amount.
