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Yuliya22 [10]
2 years ago
7

Find the perimeter simply Answer

Mathematics
1 answer:
Naddika [18.5K]2 years ago
7 0

The perimeter of the polygon of sides as 9/2, 17/2, 52/5, 52/5, 64/5, 59/4 is 1227 /20.

<h3>What is the perimeter of the polygon?</h3>

The perimeter of the polygon is the measure of the sum of the sides of the given figure.

The sides are given as 9/2, 17/2, 52/5, 52/5, 64/5, 59/4

The perimeter of the polygon = 9/2 + 17/2 + 52/5 + 52/5 + 64/5 + 59/4

                                                  = 26/2 + 168/5 + 59/4

                                                  = 111/4 + 168/5

                                                  = 555 + 672 / 20

                                                  = 1227 /20

Thus, The perimeter of the polygon is 1227 /20.

Learn more about perimeter here;

brainly.com/question/6465134

#SPJ1

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Step-by-step explanation:

A triangle has three sides and three angles. A right angle triangle has 90 degrees as one of the angles. The remaining two angles are complimentary. This means that the sum if the other two angles is 90 degrees.

The longest side is the hypotenuse. The shorter sides are the opposite and adjacent.

In this triangle, the hypotenuse is three inches more than twice the length of one leg. Let the length of one leg be x inches.

Hypothenuse = 2x + 3

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The diagram is illustrated in the attached photo.

Applying Pythagoras theorem,

Hypothenuse ^2 = adjacent^2 + opposite ^2

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x = 5inches because it cannot be negative.

Length of hypothenuse = 2x + 3

= 2×5 + 3 = 10 + 3 = 13 inches

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