Ask question

Ask question

All categories

3 years ago

7

Question 7 7. Which equation is true? A 831 102 = 8.310 B. 405. 103= 406,000 C. 915. 10+ = 915.000 D. 257 102 = 257.000 СА

1 answer:

OLEGan [10]3 years ago

6 0

Answer:C.

Step-by-step explanation:

You might be interested in

Hello can you please help me posted picture of question

loris [4]

The sample space will be: {1, 2, 3, 4, 5, 6}

Event A is: {Rolling 1,2 or 3}

Complement of event A will contain all those outcomes in the sample space which are not a part of event A.

So, complement of event A will be: {Rolling a 4,5 or 6}

Thus option A gives the correct answer

3 0

3 years ago

Lily plants 2 red rosebushes, 8 pink rosebushes, and 6 yellow rosebushes. What is the ratio of pink and red

andrey2020 [161]

Answer:

C. 10 : 16

Step-by-step explanation:

Attached below

4 0

3 years ago

Evaluate using <br> Definite integrals

swat32

Since $[0,4]=[0,1]\cup(1,4]$ , we can rewrite the integral as

$\displaystyle \int_0^1f(t)\;dt + \int_1^4 f(t)\; dt$

Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:

$\displaystyle \int_0^1f(t)\;dt = \int_0^11-3t^2\;dt,\quad \int_1^4 f(t)\; dt = \int_1^4 2t\; dt$

Both integrals are quite immediate: you only need to use the power rule

$\displaystyle \int x^n\;dx=\dfrac{x^{n+1}}{n+1}$

to get

$\displaystyle \int_0^11-3t^2\;dt = \left[t-t^3\right]_0^1,\quad \int_1^4 2t\; dt = \left[t^2\right]_1^4$

Now we only need to evaluate the antiderivatives:

$\left[t-t^3\right]_0^1 = 1-1^3=0,\quad \left[t^2\right]_1^4 = 4^2-1^2=15$

So, the final answer is 15.

4 0

3 years ago

Math HELP PLEASEE URGENT NOWWWWWW MATH!!!!

Viefleur [7K]

Answer:

A

Step-by-step explanation:

Answer is the first choice. you can tell by the notation.

5 0

3 years ago

Read 2 more answers

The difference of two numbers is 57. the larger number is three less than six times the smaller number. find the numbers.

Sauron [17]

The smaller number is twelve the larger number is 69

6 0

3 years ago