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Furkat [3]
3 years ago
8

I WILL GIVE BRAINLIEST IF IT'S CORRECT AND THE BEST ANSWER

Mathematics
1 answer:
Papessa [141]3 years ago
8 0

Answer:

What is the median amount of salt left

Step-by-step explanation:

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PLEASE HELP!!<br><br> what is the arrow pointing to? (l<br><br> CHECK THE PHOTO
evablogger [386]

Answer:

3.7

Step-by-step explanation:

each tick represents .1 unit

7 0
3 years ago
Evaluate the expression: (–2)2 + (–42) + (18 – 23).
marta [7]

Answer:

-51 (no options are matching)

Step-by-step explanation:

Given: (–2)2 + (–42) + (18 – 23).

we know, 2*2 = 4, and in integer multiplication if any negative integer is multiplied with positive integer, then the result will have a negative sign.

= -4 + (-42) + (18 – 23)

Here, we have open the brackets, and written the respective signs with the integers,

= - 4 - 42 - 5

now, we will perform the integer addition. Adding all the positives together & he negative numbers together

= -51

PS: It happens to be that none of the given options match with the correct answer. But, i have solved taking the expression, i hope it helps

6 0
3 years ago
Read 2 more answers
What 2 numbers multiply to -18 and add up to -4
ivann1987 [24]

Answer:

-9 x 1 x 1 x 1 x 2 = (-18)

-9 + 1 + 1 + 1 + 2 = (-4)

5 0
3 years ago
Answer only the last question where it says (why can no angel)
Igoryamba
Because three points of the angle have to be named ex; angle ABC
8 0
3 years ago
Find Horizontal and Vertical asymptotes for y=(x^2 -9)/(4x^2 +1)
Gnom [1K]

Answer: Horizontal asymptote is \dfrac{1}{4} and vertical asymptotes are \pm \dfrac{1}{2i}

Step-by-step explanation:

Since we have given that

y=\dfrac{x^2-9}{4x^2+1}

We need to find the horizontal and vertical asymptotes.

Since vertical asymptotes will occur where the denominator becomes zero.

So, here denominator is 4x^2+1

Now,

4x^2+1=0\\\\4x^2=-1\\\\x^2=\dfrac{-1}{4}\\\\x=\pm \dfrac{1}{2i}

And the horizontal asympototes will occur when the coefficient of higher degree of numerator is divided by coefficient of higher degree of denominator.

y=\dfrac{1}{4}

Hence, horizontal asymptote is \dfrac{1}{4} and vertical asymptotes are \pm \dfrac{1}{2i}

8 0
3 years ago
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