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Angelina_Jolie [31]

3 years ago

11

One telephone company charges $16.95 per month and $0.05 per minute for local calls. Another company charges $22.95 per month an

d $0.02 per minute for local calls. For what number of minutes of local calls per month is the cost of the plans the same?

2 answers:

Burka [1]3 years ago

8 0

Answer:

200 minutes

Step-by-step explanation:

To find this, you should first set up an equation. Since you are trying to find the point where both plans cost the same, set them equal to each other. Let <em>x</em> be the cost for both. Write the equation:

$16.95+0.05x=22.95+0.02x$

We place the x with the cost per minute because this is what you are trying to find. We add the cost per month.

Solve for x. Subtract 16.95 from both sides and simplify:

$16.95-16.95+0.05x=22.95-16.95+0.02x\\0.05x=6+0.02x$

Subtract 0.02x from both sides:

$0.05x-0.02x=6+0.02x-0.02x\\0.03x=6$

Divide both sides by 0.03:

$\frac{0.03x}{0.03}=\frac{6}{0.03}\\ x=200$

At 200 minutes, the cost for both plans would be the same.

USPshnik [31]3 years ago

5 0

Answer:.03x=6

Step-by-step explanation x=200 minutes

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