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coldgirl [10]
3 years ago
7

If f(x)=3x^2 and g(x)=4x^3, what is the degree of (f*g)(x)?

Mathematics
2 answers:
crimeas [40]3 years ago
4 0
F(x) = 3x^2
g(x) = 4x^3

(f * g)(x) = 3x^2 * 4x^3 = 12x^(2 + 3) = 12x^5

the degree of (f * g)(x) is 5 <==
Westkost [7]3 years ago
3 0
3x^2 * 4x^3 = 12x^5

Answer is degree 5
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What are the solutions of the equation x^4 + 95x^2 - 500= 0? Use factoring to solve
Artist 52 [7]
1) given x^4 + 95x^2 - 500

2) split in two factors with common factor term x^2: (x^2 + )(x^2 - )

3) find two numbers that add up 95 and their product is - 500:

=> 100*(-5) = - 500 and 100 - 5 = 95

=> (x^2 + 100)(x^2 - 5)

4) factor x^2 - 5 = (x + √5) (x - √5)

5) write the prime factors: (x^2 + 100) (x + √5) (x -√5)

6) find the solutions:

x^2 + 100 = 0 => not possible

x + √5 = 0 => x = - √5

x - √5 = 0 => x = √5


Answer: x = √5 and x = - √5
4 0
3 years ago
−3/4+(1/10÷2/5) PLZ HELP
Rzqust [24]

−3/4+(1/10÷2/5)

parenthesis first

1/10 divided by 2/5

copy dot flip

1/10 * 5/2

5/20

1/4

−3/4+(1/10÷2/5)

-3/4 + 1/4

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divide top and bottom by 2

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8 0
3 years ago
Read 2 more answers
Find n so that the number sentence below is true:
adell [148]

Answer: n=6

Step-by-step explanation:

2^3 x 4^3 = 2^3 x 2^n = 2^9

(2×2×2) ×(4×4×4) = (2x2x2) ×2^n=(2x2x2x2x2x2x2x2x2)

8 x 64 = 8x 2^n = 512

512= 8x 2^n = 512

divide all through by 8 so that 2^n can stand alone

512/8 = (8x 2^n)/8 = 512/8

64 = 2^n = 64

express 64 as a base of 2

2^6 = 2^n = 2^6

since they all have same base, cancel out the base.

therefore,

6=n=6

n = 6

6 0
2 years ago
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