The area of poster is 32 square inches
<em><u>Solution:</u></em>
Let "a" be the length of rectangle
Let "b" be the width of rectangle
<em><u>The length of Joseph’s rectangular poster is two times it’s width</u></em>
Therefore,
Length = 2 times width
a = 2b --------- eqn 1
The perimeter is 24 inches
<em><u>The perimeter of rectangle is given by formula:</u></em>
<em><u>Substituting the given values we get,</u></em>
Substitute b = 4 in eqn 1
a = 2(4)
a = 8
Thus we got,
Length = 8 inches
Width = 4 inches
<em><u>The area of rectangle is given by formula:</u></em>
Thus area of poster is 32 square inches
Take the original cost and multiply 0.18 to it. then take the product of that and add it to the original number to get the total cost.
Answer:
A) 0 , B) 0.0199 , C) 200
Step-by-step explanation:
Let X denotes no. of computers fail on day
X ~ Bin (n = 4 , p = 0.05)
A] P (X = x) = (n c x) p^x q^n-x
P (X = 4) = (4 c 4) (0.005)^4 (0.995)^0
(0.05)^4 ~ 0
B] P (X <u>></u> 1) = 1 - P (X < 1) = 1 - P (X = 0)
1 - { ( 4 c 0) (0.005)^0 (0.995)^ 4 }
1 - (0.995)^ 4 ~ 0.0199
C] Let Y depict mean number of days until a specific computer fails
Y ~ Geom (p = 0.005)
Mean = E (Y) = 1/p = 1/0.05 = 200
Step-by-step explanation:
acc to BODMAS RULE
Brackets Of Division Multiply Add Subract
2x+12×2×2-3x+4x-6x-4
2x-3x+4x-6x+12×2×2-4
6x-6x-3x+48-4
-3x+44
Answer:
I'm gonna go with C
Step-by-step explanation:
Don't take my word for it