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Dmitry_Shevchenko [17]
3 years ago
10

Need help on this one

Mathematics
1 answer:
marysya [2.9K]3 years ago
6 0
The answer is .....................1600......
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One day, a person went to a horse racing area. Instead of counting the number of humans an horses, he conuted 74 heads and 196 l
Komok [63]
A human has 1 head and 2 legs.
A horse has 1 head and 4 legs.

Let's make two equations from what we know.

There were a total of 74 heads.
There were a total of 196 legs.

Let's call humans 'x' and horses 'y'

The total number of heads were 74.
Humans have 1 head, and so do horses.

Our first equation is:
x + y = 74

There were a total of 196 legs. 
Humans have 2 legs, and horses have 4 legs.

Our second equation is:
2x + 4y = 196

Our two equations are:

x + y = 74
2x + 4y = 196

We need to solve this system of equations to find out how many humans and horses were at this racing event.

Multiply the first equation by 2.

2(x + y) = 2(74)
2x + 2y = 148

Our two equations are:

2x + 2y = 148
2x + 4y = 196

Subtract the first equation from the second equation.

2x - 2x + 2y - 4y = 148 - 196
2y - 4y = 148 - 196
-2y = - 48

Divide both sides by -2

y = 24

That means that there were 24 horses.

We can plug back in y = 24 into our first equation to find out how many humans there were.

x + y = 74
x + 24 = 74
x + 24 - 24 = 74 - 24
x = 50

There were 50 humans.

At the horse racing event, there were 24 horses and 50 humans.

Your final answer is B. 24 horses and 50 humans.

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Since x is the days And y is the entries And there are 8entries already the equation should be y=x+8
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three and five hundreths

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Step-by-step explanation:

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