2 ways in solving this hope it helped
Answer:
Hopes it helps
Step-by-step explanation:
The Quadratic Polynomial is
2 x² +x -4=0
Using the Determinant method to find the roots of this equation
For, the Quadratic equation , ax²+ b x+c=0
(b) x²+x=0
x × (x+1)=0
x=0 ∧ x+1=0
x=0 ∧ x= -1
You can look the problem in other way
the two Quadratic polynomials are
2 x²+x-4=0, ∧ x²+x=0
x²= -x
So, 2 x²+x-4=0,
→ -2 x+x-4=0
→ -x -4=0
→x= -4
∨
x² +x² +x-4=0
x²+0-4=0→→x²+x=0
→x²=4
x=√4
x=2 ∧ x=-2
As, you will put these values into the equation, you will find that these values does not satisfy both the equations.
So, there is no solution.
You can solve these two equation graphically also.
Answer:
Step-by-step explanation:
Given the volume of the cylindrical soup expressed as V = πr³+ 7πr²
From V = πr³ + 7πr²;
factor out the common variable
V = πr³ + 7πr²
V = πr²(r+7) ... 1
The original volume of a cylinder V = πr²h .... 2 where;
r is the radius of the cylinder
h is the height of the cylinder
Equating equation 1 and 2, we will have;
πr²(r+7) = πr²h
Divide both sides by πr²
πr²(r+7)/ πr² = πr²h/ πr²
r+7 = h
h = r+7
<em>Hence the factor in the context given is equivalent to the height of the cylinder written as a function of its radius r</em>.<em> The statement means that the height of the cylindrical soup is 7 more than its radius.</em>
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Answer:
A.(170+30)-41
Step-by-step explanation:
(170+30)-41=170+(30-41)
200-41=170+(-11)
159=170-11
159=159
