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inessss [21]
3 years ago
7

Two chords Please help

Mathematics
2 answers:
viktelen [127]3 years ago
6 0
I think the answer is 29
Sphinxa [80]3 years ago
5 0

Answer:

             

Step-by-step explanation:

You might be interested in
What value of x makes the following equation true x + 10 = 18​
Mademuasel [1]
X+10=18. |-10 from both sides
x+10-10=18-10
x=8
6 0
3 years ago
Read 2 more answers
A 3 ounce serving of tuna provides 21 grams of protein. Use equivalent ratios to find how many grams of protein are in 9 ounces
denis-greek [22]

Answer:

There would be 63 grams of protein in 9 ounces of tuna.  

Step-by-step explanation:

Equivalent ratios compare two different quantities the have the same rate regardless of the amount.  In this example, for every 3 ounces of tuna, there are 21 grams of protein.  We can write this as a ratio of:  3/21.  Like fractions, we can simplify ratios by dividing the numerator and denominator by the same greatest common factor.  In this case, we would divide both the numerator and denominator by 3:  (3÷3)/(21÷3) = 1/7. So, our new ratio is for every ounce of tuna, we have 7 grams of protein.  Using equivalent ratios, we can set up our ratios to solve for the grams of protein in 9 ounces of tuna:  1/7 = 9/x.  Since we have to multiply both the numerator and denominator by the same factor, in this case 9, then our x = 63 grams of protein.

5 0
3 years ago
Compute the standard error for sample proportions from a population with proportion p= 0.55 for sample sizes of n=30, n=100 and
Pani-rosa [81]

Given Information:

Population proportion = p =  0.55

Sample size 1 = n₁ = 30

Sample size 2 = n₂ = 100

Sample size 3 = n₃ = 1000

Required Information:

Standard error = σ = ?

Answer:

$ \sigma_1 = 0.091 $

$ \sigma_2 = 0.050 $

$ \sigma_3 = 0.016 $

Step-by-step explanation:

The standard error for sample proportions from a population is given by

$ \sigma =  \sqrt{\frac{p(1-p)}{n} } $  

Where p is the population proportion and n is the sample size.

For sample size n₁ = 30

$ \sigma_1 =  \sqrt{\frac{p(1-p)}{n_1} } $

$ \sigma_1 =  \sqrt{\frac{0.55(1-0.55)}{30} } $

$ \sigma_1 = 0.091 $

For sample size n₂ = 100

$ \sigma_2 =  \sqrt{\frac{p(1-p)}{n_2} } $

$ \sigma_2 =  \sqrt{\frac{0.55(1-0.55)}{100} } $

$ \sigma_2 = 0.050 $

For sample size n₃ = 1000

$ \sigma_3 =  \sqrt{\frac{p(1-p)}{n_3} } $

$ \sigma_3 =  \sqrt{\frac{0.55(1-0.55)}{1000} } $

$ \sigma_3 = 0.016 $

As you can notice, the standard error decreases as the sample size increases.

Therefore, the greater the sample size lesser will be the standard error.

8 0
4 years ago
Colin invests £980 into his bank account. He receiv 0.3% per year simple interest. How
guapka [62]

Answer: 1,000.77

Step-by-step explanation:

After 1 year: 980 + 0.3% = 982.94

After 2 years: 982.94 + 0.3% = 985.89

After 3 years: 985.89 + 0.3% = 988.85

After 4 years: 988.85 + 0.3% = 991.82

After 5 years: 991.82 + 0.3% = 994.80

After 6 years: 994.80 + 0.3% = 997.78

After 7 years: 997.78 + 0.3% = 1,000.77

Brainliest?

7 0
2 years ago
If line n bisects segment CE, find the positive value of x.<br><br> A.6<br> B.10<br> C.15<br> D.9
givi [52]

9514 1404 393

Answer:

  D.  9

Step-by-step explanation:

The segment lengths are equal, so ...

  x^2 = 90-x

  x^2 +x -90 = 0 . . . . . . add x-90 to put in standard form

  (x +10)(x -9) = 0 . . . . . factor

The solutions are the values of x that make the factors zero: -10, 9.

The positive value of x is 9.

8 0
3 years ago
Read 2 more answers
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