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vredina [299]
4 years ago
7

What is the next term in the pattern? 1, -1, 2, -2, 3,... 4 -4 3 -3

Mathematics
2 answers:
Alona [7]4 years ago
8 0

Answer:

-3, 4, -4

Hope this helps :)

DerKrebs [107]4 years ago
8 0

Answer:

-3

Step-by-step explanation:

they all go to the negative side of them every other number. Hope that this helps you and have a great day :)

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One of diagonals of a parallelogram is its altitude. What is the length of this altitude, if its perimeter is 50 cm, and the len
balandron [24]

The sum of adjacent sides is half the perimeter, so is 25 cm. Since the side lengths are consecutive numbers, they are both nearly half of 25 cm. One side is 12 cm, the other is 13 cm.

These lengths, then, are one leg and the hypotenuse of the right triangle that makes up half the parallelogram. The other leg, the altitude, is found using the Pythagorean theorem (or your knowledge of Pythagorean triples). It is

... altitude = √((13 cm)² -(12 cm)²) = √(25 cm²) = 5 cm

The length of the altitude is 5 cm.

6 0
3 years ago
Write an expression that means "the sum of six and the product of three and d"
kolezko [41]

Answer:

6+3d

Step-by-step explanation:

Sum would be adding 6 and a number, and product is 3 and d. So, it would be 6+3d.

3 0
3 years ago
What is the value of the fourth term in a geometric sequence for which a1 =<br> 30 and r= 1/2
Tcecarenko [31]

Answer:

3¾

Step-by-step explanation:

Geometric sequence also known as geometric progression, can be said to be a sequence with a constant ratio between the terms.

Formula for geometric sequence:

a^n = a ( n-1 ) * r

Given:

First term, a1 = 30

ratio, r = ½

Required:

Find the fourth term

Where, the first term, a¹ = 30

Second term: a² = 30 * ½ = 15

Third term: a³ = 15 * ½ = 7.5

Fourth term: a⁴ = 7.5 * ½ = 3.75 = 3¾

Therfore the fourth term of the geometric sequence is 3¾

6 0
3 years ago
Choose all the factors of 5. (Check all that apply.)<br><br><br> 4<br> 1<br> 3<br> 2<br> 5
Artyom0805 [142]
5 is the only factor of 5
5 0
3 years ago
Read 2 more answers
a projectile is thrown upward so that it's distance above the ground after T seconds is H equals -16t^2 + 672 T. After how many
Arada [10]

Step-by-step explanation:

T = time in seconds

H = distance

Tground = time to return to ground

Tmax = time at maximum height

H = -16T^2 + 672T...eqn 1

projectile returns to ground at H =0,

subs for H in eqn 1...

0 = -16T^2 + 672T

solving for T we get...

16T^2 = 672T

=> Tground = 42secs

Tmax = 0.5 Tground = 21secs

4 0
3 years ago
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