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mr Goodwill [35]
3 years ago
9

. Write your answer in simplest form. 7/3 divided 9

Mathematics
2 answers:
Ymorist [56]3 years ago
5 0
The answer is 7/27.......

Kryger [21]3 years ago
4 0

Answer:

7/27

Step-by-step explanation:

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A set of electric toothbrush prices are normally distributed with a mean of 87 dollars and a standard deviation of
Studentka2010 [4]

Answer:

The proportion of electric toothbrush prices are between 104.60 dollars and 108.20 dollars is 0.0099

Step-by-step explanation:

A set of electric toothbrush prices are normally distributed with a mean of 87 dollars and a standard deviation of  8 dollars.

Mean = \mu = 87

Standard deviation = \sigma = 8

We are supposed to find proportion of electric toothbrush prices are between 104.60 dollars and 108.20 dollars i.e.P(104.60<x<108.20)

Z=\frac{x-\mu}{\sigma}

At x = 104.60

Z=\frac{104.60-87}{8}

Z= 2.2

At x=108.20

Z=\frac{108.20-87}{8}

Z= 2.65

Refer the z table for p value :

P(x<108.20)-P(x<104.60)=P(Z<2.65)-P(Z<2.2)=0.9960-0.9861=0.0099

Hence The proportion of electric toothbrush prices are between 104.60 dollars and 108.20 dollars is 0.0099

4 0
3 years ago
The area of a triangular block is 49 square inches. If the base of the triangle is twice the height, how long are the base and t
andrezito [222]
1) Formula: area = height * base / 2

2) Call x the height:

height = x

base = 2x

3) State the equation:

(x)(2x) = 49 in^2

4) Solve the equation:

2x^2 = 49 in^s

x^2 = (49/2) in^2

x = √(49/2) in

x = 7√2 / 2 in = 3.5 √2 in

5) Solution:

height = 3.5 √2 in and base = 7√2 in

6) Verification: area = (7√2 in) (3.5√2 in) = 49 in^2

Answer: height = 3.5√2 in and base = 7√2 in.
5 0
3 years ago
Order the following numbers from least to greatest.
gogolik [260]

Answer:

-45, 12, 83, 90

Step-by-step explanation:

5 0
2 years ago
Question :-
DochEvi [55]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  +  \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } } \bigg ) {}^{2}  +  \bigg( \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}  + 2 \cdot \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  \cdot \sqrt{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{1}{7 +  \sqrt{5} }  + 7 +  \sqrt{5}  + 2

\qquad \sf  \dashrightarrow \: \dfrac{49 + 7 \sqrt{5} + 7 \sqrt{5} + 5 + 14 + 2 \sqrt{5}   }{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{68+ 16 \sqrt{5}    }{7 +  \sqrt{5} }

5 0
2 years ago
Let f(x) = (x+3) (x+1)^n ( x+2) ² what is the multiplicity of the zero of f at x=2? ​
nekit [7.7K]

Answer:

is c

Step-by-step explanation:

6 0
3 years ago
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