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Gennadij [26K]
3 years ago
5

X/3 + 4<6 pls help will mark branliest

Mathematics
2 answers:
Llana [10]3 years ago
6 0

Answer:

X = 5.9- meaning 5.9 or anything under that or lets just say 5 because 5/3 = 1.6 + 4 = 5.6

Step-by-step explanation:

Have a nice day

sorry if its wrong

Agata [3.3K]3 years ago
3 0

Answer:

x < 6

Step-by-step explanation:

\frac{x}{3}+4 < 6

Subtract 4 form both sides

\frac{x}{3}

Multiply both sides by 3

x < 2*3\\\\x < 6

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If a quadratic equation has a real root, what do you know about the other roots of the equation? Explain.
notsponge [240]

Answer:

A Quadratic Equation can have upto 2 roots maximum. So,if one of the roots is a Real number, there are following two possibilities:

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7 0
3 years ago
Simplify the radical expression. √45 + √20 - √5
viva [34]
√45 = √9√5 = 3√5
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answer = 4√5
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5 0
3 years ago
Find the perimeter of this shape
telo118 [61]
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A car travels at 20 meters per second.
7nadin3 [17]

Answer:

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3 0
3 years ago
Read 2 more answers
The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain? {5, 8} {-5, -8} {3, 8} {4, 7} {4, 8}
Savatey [412]
The range is the ouutput from inputing the input
basically
25=k²+2k+1 and 64=k²+2k+1
the values that satisfy both equations (not at the same tim) are the valuess that are the domain
solve each
25=k²+2k+1
minus 25 both sides (or recognize the perfect square trinomial, but anyway)
0=k²+2k-24
factor
0=(k+6)(k-4)
set to zero
k+6=0
k=-6
k-4=0
k=4
k=-6 or 4

64=k²+2k+1
minus 64 both sides
0=k²+2k-63
facor
0=(k-7)(k+9)
set to zer
k-7=0
k=7
k+9=0
k=-9
k=-9 or 7



so the domain has the numbers
-9,-6,4,7
it seems we only want the positive square roots so
answer is {4,7} is the domain
3 0
3 years ago
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