2000???????????!!??!!??!??!??!?!!??!??!??!
The answer:
the full question is as follow:
if A+B-C=3pi, then find sinA+sinB-sinC
first, the main formula of sine and cosine are:
sinC = 2sin(C/2)cos(C/2)
sinA +sinB = 2sin[(A+B)/2]cos[(A-B)/2]
therefore:
sinA+sinB-sinC = 2sin[(A+B)/2]cos[(A-B)/2] - 2sin(C/2)cos(C/2)
sin[(A+B)/2] = cos(C/2)
2sin(C/2)cos(C/2) = cos[(A+B)/2
and
A+B-C=3 pi implies A+B =3 pi + C, so
cos[(A+B)/2] = cos [3 pi/2 + C/2]
and with the equivalence cos (3Pi/2 + X) = sinX
sinA+sinB-sinC = cos(C/2)+ sin(C/2)
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ab i think that is the answer <span />
$5 each car
3 hours = 12 cars
÷3 ÷3
1 hours = 4 cars
×8 ×8
8 hours = 32 cars
32 cars × $5 per car =
$160
They earned $160 in 8 hours, from washing 32 cars.
Answer:
The brainliest!
Step-by-step explanation:
c= 7/6k- 17(7/6)
6/7c = k - 17
k = 6/7c+17
