Check the picture below.
now, if AC is that much, recall, BD is the midsegment, thus AB = BC, so AB is just one of the equal halves of AC, so, AB is AC/2.
4 1/8-2 3/4= 4 1/8 - 2 6/8= 1 3/8
2 3/5 + 1 5/6 = 2 18/30 + 1 25/30= 3 43/30 = 4 13/30
8 9/12 + 2 3/8= 8 18/24 + 2 9/24= 10 27/24 = 11 3/24= 11 1/8
3 1/3 - 1 1/2= 3 2/6 - 1 3/6 = 2 8/6 - 1 3/6= 1 5/6
Answer:
If you want to know what the probability is to get at least one Heads, then that is the same as the probability of all the events (100%, or 1) minus the probability of getting all Tails.
There are 100 coins. 99 are fair, 1 is biased with both sides as heads. With a fair coin, the probability of three heads is 0.53=1/8. The probability of picking the biased coin: P(biased coin)=1/100.
Step-by-step explanation:
Counting by 10 is called base 10
