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Liono4ka [1.6K]
3 years ago
9

Which equation can be used to solve the problem 180 is 40% of what number

Mathematics
2 answers:
Kruka [31]3 years ago
6 0

Answer:

40/100 * x = 40

Solve for x. Hope this helps

Alex787 [66]3 years ago
6 0

Answer:

180= 0.4x

x= 450

Step-by-step explanation:

180= 40% of x

180= 0.4x

x= 180/0.4

x= 450

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X - 49.5 = 15
x = 15 + 49.5
x = 64.5
8 0
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Tom owns a $160,000 home, for which he has a 30-year mortgage in the amount of $900 a month. Once he has paid off the mortgage,
julsineya [31]

A he will pay $164,000

8 0
3 years ago
Read 2 more answers
Please help!! I don’t get it
Marrrta [24]

Answer:

Each hotdog costs $1.65

Each juice drink costs $1.05

Step-by-step explanation:

Let's begin by letting x represent the number of hot dogs and y the number of juice drinks.

The Baxter family bought 6 hot dogs and 4 juices for $14.10.

6x + 4y = 14.10

The Farley family bought 3 hot dogs and 4 juices for $9.15.

3x + 4y = 9.15

Now, we subtract these equations.

6x + 4y = 14.10\\- (3x + 4y = 9.15)

Since y has reversed coefficients, it gets eliminated. Now solve for x.

6x+4y-3x-4y=14.1-9.15\\3x = 4.95\\\frac{3x}{3} = \frac{4.95}{3}

\frac{4.95}{3} = 1.65

x = 1.65

NOW, we find y by substituting x with 1.65 (in either equation).

We'll use the first equation.

6x + 4y = 14.10

6(1.65) + 4y = 14.10

9.9 + 4y = 14.10\\4y = 14.1 - 9.9\\4y = 4.2

\frac{4y}{4} = \frac{4.2}{4} \\y = 1.05

x = 1.65

y = 1.05

x represents hotdogs and y represents juice drinks.

Therefore, each hotdog costs $1.65 and each juice drink costs $1.05.

<em> I hope this helps! :)</em>

6 0
3 years ago
the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th
Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : \text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. 13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130      (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. 9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270      (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups =\dfrac{\text{Sum of combined students}}{\text{combined students}}

=\dfrac{400}{40}=10

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0
3 years ago
SAVINGS ACCOUNT
yarga [219]

Answer:

$4000 was invested at 4%, 2500 was invested at 3%

Step-by-step explanation:

First and foremost the question has to be define.

Total amount raised is $6500

Savings account percentage simple interest =3%

Government Bond: 4% simple interest

Equation for amount invested at each rate:

(6500-x)0.03 + 0.04x = 235

195 - 0.03x + 0.04x = 235

0.01x = 40

x = 4000

$4000 was invested at 4%, 2500 was invested at 3%

4 0
3 years ago
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