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3 years ago

13

Solve the following system of equations by graphing.

1 answer:

never [62]3 years ago

8 0

Answer:

(x,y)=(3,1)

Step-by-step explanation:

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Simplify y^-3 <br><br> a.3/y<br> b.1/y^3<br> c.-3y<br> d.-1/y^3

nignag [31]

Answer:

b. $\frac{1}{y^3}$

Step-by-step explanation:

Here we are given $y^{-3}$ and are asked to simplify it. We are going to apply the law of exponents which says that

$a^{-n}=\frac{1}{a^n}$

Hence applying this rule in our problem we get, where a=y and n=3

$y^{-3}=\frac{1}{y^3}$

Hence our C) Option is correct

3 0

3 years ago

What is the solution to -2(8x – 4) < 2x + 5?<br> o xs<br> oxca<br> O x>6<br> O x<6

TiliK225 [7]

$-2(8x-4)$

3 0

2 years ago

Which parent function is graphed below

aleksandrvk [35]

Answer:

the answer for this question is c because that is the answer

4 0

3 years ago

If f(1) = 10 and f(n) = f(n = 1) – 4 then find the value of f(5).

svetoff [14.1K]

Given:

$f(1)=10$ and $f(n)=f(n-1)-4$ .

To find:

The value of f(5).

Solution:

We have,

$f(n)=f(n-1)-4$

For $n=2$ ,

$f(2)=f(2-1)-4$

$f(2)=f(1)-4$

$f(2)=10-4$

$f(2)=6$

For $n=3$ ,

$f(3)=f(3-1)-4$

$f(3)=f(2)-4$

$f(3)=6-4$

$f(3)=2$

For $n=4$ ,

$f(4)=f(4-1)-4$

$f(4)=f(3)-4$

$f(4)=2-4$

$f(4)=-2$

For $n=5$ ,

$f(5)=f(5-1)-4$

$f(5)=f(4)-4$

$f(5)=-2-4$

$f(5)=-6$

Therefore, the value of $f(5)$ is $-6$ .

5 0

3 years ago

What are the leading coefficient, constant term and degree, if any, of the algebraic expression

nasty-shy [4]

Coefficients are the numbers in from with the variable, the constant is just a number and the degree is the exponent.

6 0

3 years ago