Answer:
c=71/23
Step-by-step explanation:
I think
Divide
7/12 = <span>.583
We get answer: </span><span>D. .583</span>
Answer:
The point C is 12.68 km away from the point A on a bearing of S23.23°W.
Step-by-step explanation:
Given that AB is 50 km and BC is 40 km as shown in the figure.
From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|
=|50 sin 80° - 40 cos 20°|=11.65 km
The length of y-component of AC = |AB cos 80° - BC sin 20°|
=|50 cos 80° - 40 sin 20°|= 5 km
tan
= 5/11.65
=23.23°
AC=
km
Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.
Answer:
no diagram
Step-by-step explanation:
Answer:
25/18
Step-by-step explanation:
5/6 / 6/10
K C F
5/6 * 10/6
50/36 = 25/18