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Jlenok [28]
3 years ago
8

30 POINTS FOR THIS QUESTION PLEASE HELP ME!!

Mathematics
1 answer:
AveGali [126]3 years ago
3 0
The zeroes (where the line crosses the x-axis, these are also the solutions) and the vertex (the highest or lowest point)
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Find three consecutive positive integers such that the sum of their squares is 2354. What is the largest integer?
Ilya [14]

Answer:

The largest integer is 29.

Step-by-step explanation:

Let the consecutive positive integers are x, x+1 and x+2.

The square of sum of squares of three consecutive positive integers is 2354 such that,

x^2+(x+1)^2+(x+2)^2=2354\\\\x^2+x^2+2x+1+x^2+4+4x=2354\\\\3x^2+6x+5=2354\\\\3x^2+6x- 2349=0

It is a quadratic equation whose solution is given by :

x = 27 and x = -29

First positive integer = 27

Second positive integer = 27+1 = 28

Third positive integer = 27+2 = 29

Hence, the largest integer is 29.

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Step-by-step explanation:

9=-d+17

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9+d=17

(subtract 9 from both sides because it is the opposite of adding)

d=17-9=8

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