Question

For the function f(t) =Pe^rt , if P= 7 and r= 0.07 then what is the value of f(7) to the nearest tenth?

Answer 1

Answer:

A. 11.4  

Step-by-step explanation:

$f(t) = P e^{rt}$

Data:

P = 7

r = 0.07

Calculation:

$\begin{array}{rcl}f(t) & = &Pe^{rt}\\f(7)& = & 7 e^{(0.07 \times 7)}\\ & = & 7 e^{0.49}\\& \approx & 7 \times 1.632\\ & \approx & \mathbf{11.4}\\\end{array}$

Answer 2

Answer:

11.4

Step-by-step explanation:

JUST DID ON APEX