The formula for average velocity between two times t1 and t2 of the position function f(x) is (f(t2)-f(t1)) / (t2-t1)
Plugging the values in for the first time period we get (f(2.5)-f(2)) / (2.5-2)
=> (f(2.5)-f(2)) / 0.5
f(2) will be the same for all 4 time periods and is
48(2)-16(2)^2 = 32
Now we plugin the other values
f(2.5) = 48(2.5)-16(2.5)^2 = 20
f(2.1) = 48(2.1)-16(2.1)^2 = 30.25
etc.
f(2.05) = 31.16
f(2.01) = 31.8384
Now plug these values into the formula
(20-32)/0.5 = -24
(30.25-32)/0.1 = -17.5
etc.
= -16.8
= -16.16
Final answer:
2.5s => -24 ft/s
2.1s => -17.5 ft/s
2.05 => -16.8 ft/s
2.01 => -16.16 ft/s
Hope I helped :)
Answer:
374.1
Step-by-step explanation:
Area of Hexagon = 
The ' a ' is the side length.
So now we just plug in the values
= 374.12
Answer:
x ≤ 19
Step-by-step explanation:
The instructions here are probably "solve for x." Please include them.
4 - x + 6^2 ≥ 21
becomes 4 - x + 36 ≥ 21
Now combine like terms. 4 and 36 combine to 40: 40 - x ≥ 21, and so:
19 - x ≥ 0
Adding x to both sies results in
x ≤ 19
Please, include the instructions when you post a question. Thanks.
<h3>
Answer:</h3>
<h3>
Step-by-step explanation:</h3>
The rules of exponents tell you ...
... (a^b)(a^c) = a^(b+c) . . . . . . applies inside parentheses
... (a^b)^c = a^(b·c) . . . . . . . . applies to the overall expression
The Order of Operations tells you to evaluate inside parentheses first. Doing that, you have ...
... x^(4/3)·x^(2/3) = x^((4+2)/3) = x^2
Now, you have ...
... (x^2)^(1/3)
and the rule of exponents tells you to multiply the exponents.
... = x^(2·1/3) = x^(2/3)
None of the offered choices is correct.
The correct equation is
.. a = (2s -2ut)/t^2 . . . . . . . . parentheses are required
