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liberstina [14]
3 years ago
8

Can someone please help me this is due today!!!!!

Mathematics
2 answers:
Mnenie [13.5K]3 years ago
6 0

Answer:

sure

Step-by-step explanation:

i'll go to your profile and do your next/latest question.

steposvetlana [31]3 years ago
3 0

Answer:

sure whats up ? whats the question

You might be interested in
Jordan wants to prove △PQR≅△STU using a sequence of rigid motions. This is Jordan's proof. Translate △PQR to get △P'Q'R' with R'
aleksandr82 [10.1K]

Answer:

A. △P'Q'R' does not equal △P''Q''R''.

B. Reflecting across UT would change the orientation of the figure.

C. The sequence does not include a reflection that exchanges U and S.

D. Rotating about point U is not a rigid motion because it changes the orientation of the figure.

E. Translating point R' to Q' is a non-invertible transformation because it changes the location of P'.

(D) Rotating about U is not a rigid motion because it changes the orientation of the figure. [I think D is an incorrect answer choice.]

Step-by-step explanation:

Proof No.1

Jordan wants to prove △PQR≅△STU using a sequence of rigid motions. This is Jordan's proof. Translate △PQR to get △P'Q'R' with R'=U. Then rotate △P'Q'R' about point U to get △P''Q''R''. Since translation and rotation preserve distance, R''Q''=RQ=UT, and Q''=T. Reflect △P''Q''R'' across UT to get △P'''Q'''R''. Since reflection preserves distance, P'''R'''=PR=US, and P'''=S. A sequence of rigid motions maps △PQR onto △STU, so △PQR≅△STU.

Proof No.2

Jordan wants to prove △PQR≅△STU using a sequence of rigid motions. This is Jordan's proof. Translate △PQR to get △P'Q'R' with R'=U. Then rotate △P'Q'R about point U to get △P''Q''R'' so that R''Q'' and UT coincide. Since translation and rotation preserve distance, R''Q''=RQ=UT, and Q''=T. Reflect △P''Q''R'' across UT to get △P'''Q'''R''. Since reflection preserves distance, P'''R'''=PR=US, and P'''=S. A sequence of rigid motions maps △PQR onto △STU, so △PQR≅△STU.

8 0
3 years ago
Solve this system of equations: y = x2 – 3x + 12 y = –2x + 14 What are the solutions ?
Nuetrik [128]
Answer:
The solution to the system of equation would be the two order pairs (2,10) and (-1,16)

Explanation:
The solution means the value of x that satisfies both equations.
Therefore, we will equate the two equations given and solve for x.
The first is: y = x^2 - 3x + 12
The second is : y = -2x + 14
Equate both and solve for x as follows:
x^2 - 3x + 12 = -2x + 14
x^2 - 3x + 2x + 12 - 14 = 0
x^2 - x - 2 = 0
(x-2)(x+1) = 0
either x = 2 and y = (2)^2 - 3(2) + 12 = -2(2) + 14 = 10
or x = -1 and y = (-1)^2 - 3(-1) + 12 = -2(-1) + 14 = 16
Therefore, the solution to the system of equation would be the two order pairs (2,10) and (-1,16)

Hope this helps :)

7 0
3 years ago
Ms. Hughes has 6.5 yards of yellow fabric and 12.3 yards of blue fabric. She needs a total of 20 yards of fabric. How much more
vesna_86 [32]
Just add. 6.5+12.3= 18.8 then subtract 20-18.8= 1.2. She needs 1.2 mores yards
3 0
3 years ago
Solve for x &amp; explain work?<br> 3/4 (2x+5)=5(x+12)
koban [17]

3/4(2x + 5) = 5(x + 12)

First get rid of any fractions by multiplying my the denominator

4 x 3/4(2x + 5) = 4 x 5(x + 12)

3(2x + 5) = 20(x + 12)

Then get rid of the parentheses

6x + 15 = 20x +240

Then simplify

6x + 15 - 15 = 20x + 240 - 15

6x = 20x + 225

6x - 20x = 20x - 20x + 225

-14x = 225

Now divide on both sides

-14x/-14 = 225/-14

x = -16

5 0
3 years ago
Based on the graph, which inequality is correct for a number that is to the right of -3?
Ede4ka [16]
Positive infinity is going after three hope this helps
6 0
3 years ago
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