Explanation NEEDS to be included! No fake answers please! Brainliest for the best! Thank You!

Mathematics

2 answers:

Paha777 [63]2 years ago

6 0

Answer:

I beleive the answer is $9000

Step-by-step explanation: What is 18% of 50000?

Y is 18% of 50000

Equation: Y = P% * X

Solving our equation for Y

Y = P% * X

Y = 18% * 50000

Converting percent to decimal:

p = 18%/100 = 0.18

Y = 0.18 * 50000

Y = 9000

Anuta_ua [19.1K]2 years ago

3 0

9000 is how much is taken off, just take 18% of 50000=9000
50000-9000=41,000.
After 18% is taken off it’s $41,000
It asked for how much the gold would be worth not how much is taken off.

You might be interested in

There are 790 cal in 610 ounce bottles of apple juice how many calories are there in one 10 ounce bottle of apple juice

Akimi4 [234]

I would say 18 because 790-610= 180 and 180÷10= 18

7 0

3 years ago

Suppose you are investigating the relationship between two variables, traffic flow and expected lead content, where traffic flow

prisoha [69]

Answer:

The answers is " Option B".

Step-by-step explanation:

$CI=\hat{Y}\pm t_{Critical}\times S_{e}$

Where,

$\hat{Y}=$ predicted value of lead content when traffic flow is 15.

$\to df=n-1=8-1=7$

$95\% \ CI\ is\ (463.5, 596.3) \\\\\hat{Y}=\frac{(463.5+596.3)}{2}\\\\$

$=\frac{1059.8}{2}\\\\=529.9$

Calculating thet-critical value $t_{ \{\frac{\alpha}{2},\ df \}}=-2.365$

The lower predicted value $=529.9-2.365(Se)$

$463.5=529.9-2.365(Se)\\\\529.9-463.5=2.365(Se)\\\\66.4=2.365(Se)\\\\Se=\frac{66.4}{2.365} \\\\Se=28.076$

When $99\%$ of CI use as the expected lead content: $\to 529.9\pm t_{0.005,7}\times 28.076 \\\\=(529.9 \pm 3.499 \times 28.076)\\\\=(529.9 \pm 98.238)\\\\=(529.9-98.238, 529.9+98.238)\\\\=(431.662, 628.138)\\\\=(431.6, 628.1)$