1 answer:
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Answer:
0.28cm/min
Step-by-step explanation:
Given the horizontal trough whose ends are isosceles trapezoid
Volume of the Trough =Base Area X Height
=Area of the Trapezoid X Height of the Trough (H)
The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)
The Volume of water in the trough at any time
=8h(8+2x)
V=64h+16hx
We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles
x/h=1/4
4x=h
x=h/4
Substituting x=h/4 into the Volume, V
h=3m,
dV/dt=25cm/min=0.25 m/min
=0.002841m/min =0.28cm/min
The rate is the water being drawn from the trough is 0.28cm/min.
Answer:
No
Step-by-step explanation:
For a proportional relationship :
y = kx
Where , k = constant of proportionality
Taking the first set of data:
x = 50 ; y = 10
10 = 50k
k = 10/ 50 = 1/5
Hence, the proportional equation or relation is :
y = 1/5x
Check if this is true for other data points on the data :
Taking the second data point :
x = 85 ; check if y will be 20
From :
y = 1/5x
y = 1/5*85
y = 85/5
y = 17
Since ;
y value from the equation isn't the same as that in the table, then the table does not show a proportional relationship.
