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zaharov [31]
3 years ago
5

Your answer

Mathematics
1 answer:
irinina [24]3 years ago
3 0
Each candy bar costed a total of $4
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Find the length of the arc of the circular helix with vector equation r(t) = 2 cos t i + 2 sin t j + tk from the point (2, 0, 0)
USPshnik [31]

\vec r(t)=2\cos t\,\vec\imath+2\sin t\,\vec\jmath+t\,\vec k

\implies\vec r'(t)=-2\sin t\,\vec\imath+2\cos t\,\vec\jmath+\vec k

\implies\|\vec r'(t)\|=\sqrt{(-2\sin t)^2+(2\cos t)^2+1^2}=\sqrt5

Then the length of the arc is

\displaystyle\int_0^{2\pi}\|\vec r'(t)\|\,\mathrm dt=\sqrt5\int_0^{2\pi}\mathrm dt=2\sqrt5\,\pi

4 0
3 years ago
Simplify 4^3•4^5.<br> help asap !
Julli [10]

Answer:

D

Step-by-step explanation:

when there are exponents with same bases multiplied by each other, keep the base and add the exponents

4^(3)+4^(5)=4^8

4^8 is D in this question

7 0
3 years ago
Use the rule x + 7 to find the missing number in the table.
dexar [7]

Step-by-step explanation:

<u>Given:</u>

  • Rule, x + 7.
  • Table values.

The rule is telling us to add 7 to the given value of x.

Add 7 to 12.

7 + 12 = 19

The missing number is 19.

3 0
2 years ago
100p for an answer please
Rainbow [258]
So from solving the problem, we know that the answer must equal -28.

When you solve all of the given options, we find that the only one that does equal -28 would be A.) (-6)(4) + (-6)(2/3).

When I doubt, solve it out. I hope I could help!
7 0
3 years ago
Write an equation in point-slope form of the line that passes through the point 4,-1and has slope of -5
Basile [38]

Answer:

y=-5+19

Step-by-step explanation:

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

To start, you know what m is; it's just the slope, which you said was -5. So you can right away fill in the equation for a line somewhat to read:

y=-5x+b.

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(4,-1). When x of the line is 4, y of the line must be -1.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: . b is what we want, the -5 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (4,-1).

So, why not plug in for x the number 4 and for y the number -1? This will allow us to solve for b for the particular line that passes through the point you gave!.

(4,-1). y=mx+b or -1=-5 × 4+b, or solving for b: b=-1-(-5)(4). b=19.

6 0
3 years ago
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