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olga_2 [115]
3 years ago
8

Triangle P=27,Q=40,P=33 law of sines round measures to the nearest tenth

Mathematics
1 answer:
nordsb [41]3 years ago
5 0
For the law of sines, you would apply it in this particular problem like so:
Since P is 27, its angle is 33 and Q's length is 40; you would set it up like this
<u />40/SinQ = 27/Sin33, multiply 40 with Sin33, then it would be 40Sin33, then divide it by 27. The result should be 40Sin33/27 = X

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Someone please help me
Lesechka [4]

If these 2 triangles are similar to each other, the corresponding sides have to exist in proportion to one another. The angles would be exactly the same (side length doesn't matter at all!). Going from the bigger triangle to the smaller, KL corresponds to RS; LJ corresponds to SQ; JK corresponds to QR. The ratio of KL:RS is 5:1; the ratio of LJ:SQ is 5:1; the ratiio of JK:QR is 5:1. That means that the sides are all proportionate and the triangles are similar by the SSS postulate. Now that we know that the triangles are similar, we can say that all the corresponding angles are the same by CPCTC but we had to determinte side similiarity first. Your answer is the second choice, SSS

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