Answer:
I'm not sure but I think the answer is 2187 X^ (14) Y^ ( 42)
Step-by-step explanation:
(3x^2y^6)^7
3^(7) x (X^)^(7) x ( Y ^(6)^(7)
= 2187 X^ 14)Y^( 42)
The length and width of a new rectangle playing field are 214 yards and 52 yards respectively.
<h3>What is the area of the rectangle?</h3>
It is defined as the area occupied by the rectangle in two-dimensional planner geometry.
The area of a rectangle can be calculated using the following formula:
Rectangle area = length x width
We have:
The length of a new rectangle playing field is 6 yards longer than quadruple the width.
Let's suppose the length is l and width is w of a rectangle:
From the problem:
l = 6 + 4w
Perimeter P = 2(l + w)
532 = 2(l + w)
Plug l = 6+4w in the above equation:
532 = 2(6 + 4w + w)
266 = 6 + 5w
260 = 5w
w = 52 yards
l = 6 +4(52) = 214 yards
Thus, the length and width of a new rectangle playing field are 214 yards and 52 yards respectively.
Learn more about the area of rectangle here:
brainly.com/question/15019502
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9514 1404 393
Answer:
x = 1 or 5
Step-by-step explanation:
The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

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<em>Comment on "cross multiply"</em>
Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.
What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.

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