Answer:
To get number of neutrons, you must have the mass number and atomic number of that atom.
atomic number is number of protons
Consider the redox reaction below talking place in certain electro chemical cell: Cu(s)+cu^2+(aq) -------> Cu^2+(aq) + Cu (s)
1 answer:
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The characteristics of the graphic representation are to find the scales and make the best graphic, in the attachment we have the points plotted
The graphical representation is one of the best methods to see the relationships between groups of data and to be able to find the functional relationships between them.
In this case, it is requested to make a scatter plot where the measured temperature is placed on the x-axis and the heat on the y-axis.
In the attachment we can see a graph with the requested data, the most important part of finding these graphs is looking for the scales
x-axis
scale x =
y-axis
scale y =
In general, the paper is 20 x 30 cm, we select the shortest part as the x axis
scale x =
scale x = 1º
Let's find the scale on the axis and the maximum value is 54000 and the minimum value is 3800, as the minimum value is much less than the maximum value, let's set this value to zero
scale y =
scale y = 1800
To facilitate marking the values, we select a slightly larger scale,
Selected scale
scale y = 2000 \frac{j}{cm \ paper}
Let's mark the points.
From observing these graph we see;
- The relationships are linear
- For the same material the amount of heat necessary to reach the same temperature is proportional to the mass of the material
Using the characteristics of the graphical representation, it is possible to find the scales and make the best graph
Learn more here: brainly.com/question/12511806
Answer:
Explanation:
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In this case, since the precipitation of the lead iodide is related to the iodide ion in solution, if we make react lead (II) nitrate with an iodide-containing salt, a possible chemical reaction would be:
In such a way, since 15.71 mL of a 0.5770-M solution of lead (II) nitrate precipitates out lead (II) iodide, we can first compute the moles of lead (II) nitrate in the solution:
Next, since there is a 1:2 mole ratio between lead (II) nitrate and iodide ions, we compute the moles of those ions:
Finally, since the mixing of the two solutions produce a final volume of 40.71 mL (0.04071 L), the resulting concentration (molarity) of the iodide ions in the student's unknown turns out:
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