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beks73 [17]
1 year ago
15

Which of the following is the correct set-up for the problem: How many grams of water will be produced from 3.2 moles of oxygen

and an excess of C2H4?​

Chemistry
1 answer:
suter [353]1 year ago
6 0

Option C is the correct set of the problem for mass of water produced by 3.2 moles of oxygen and an excess ethene.

<h3>Reaction between oxygen and ethene</h3>

Ethene (C2H4) burns in the presence of oxygen (O2) to form carbon dioxide (CO2) and water (H2O) along with the evolution of heat and light.

C₂H₄  + 3O₂   ----- > 2CO₂ + 2H₂O

from the equation above;

3 moles of O₂ ---------> 2(18 g) of water

3.5 moles of O₂ ----------> x

x = 3.2 \times [\frac{2 \ moles \ H_2O}{3 \ moles \ O_2}  ] \times[ \frac{18.02 \ g \ H_2O}{1 \ mole \ H_2O} ]

Thus, option C is the correct set of the problem for mass of water produced by 3.2 moles of oxygen and an excess ethene.

Learn more about reaction of ethene here: brainly.com/question/4282233

#SPJ1

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To synthesize information means to A. read or view it objectively. B. take it apart and examine it. C. eliminate it as irrelevan
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The correct answer is "D".

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Consider the titration of 30.0 mL of 0.050 M NH3 with 0.025 M HCl.
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Answer:

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Explanation:

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V₂ = final volume .

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3 years ago
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