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beks73 [17]
1 year ago
15

Which of the following is the correct set-up for the problem: How many grams of water will be produced from 3.2 moles of oxygen

and an excess of C2H4?​

Chemistry
1 answer:
suter [353]1 year ago
6 0

Option C is the correct set of the problem for mass of water produced by 3.2 moles of oxygen and an excess ethene.

<h3>Reaction between oxygen and ethene</h3>

Ethene (C2H4) burns in the presence of oxygen (O2) to form carbon dioxide (CO2) and water (H2O) along with the evolution of heat and light.

C₂H₄  + 3O₂   ----- > 2CO₂ + 2H₂O

from the equation above;

3 moles of O₂ ---------> 2(18 g) of water

3.5 moles of O₂ ----------> x

x = 3.2 \times [\frac{2 \ moles \ H_2O}{3 \ moles \ O_2}  ] \times[ \frac{18.02 \ g \ H_2O}{1 \ mole \ H_2O} ]

Thus, option C is the correct set of the problem for mass of water produced by 3.2 moles of oxygen and an excess ethene.

Learn more about reaction of ethene here: brainly.com/question/4282233

#SPJ1

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Explanation:

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8 0
2 years ago
What is the total pressure of air in lungs of an individual with oxygen at 100. mmHg, nitrogen at 573 mmHg, carbon dioxide at 0.
ryzh [129]

Answer: The total pressure of air in lungs of an individual is 760.28 mm Hg

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_A+p_B+p_C...

Given : p_{total} =total pressure of gases = ?

p_{O_2} = partial pressure of oxygen = 100 mm Hg

p_{N_2} = partial pressure of nitrogen = 573 mm Hg

p_{CO_2} = partial pressure of Carbon dioxide = 0.053 atm = 40.28 mm Hg(1 atm = 760 mmHg)

p_{H_2O} = partial pressure of water vapor = 47 torr = 47 mm Hg  (1torr=1 mm Hg)

putting in the values we get:

p_{total}=(100+573+40.28+47)mmHg

p_{total}=760.28mmHg

Thus the total pressure of air in lungs of an individual is 760.28 mm Hg

5 0
3 years ago
_Al2O3+heat=_Al+_O2​
Natalka [10]

Answer:

6.

2AI2O3 + heat ->  4AI + 3O2

Reaction type: Combustion

7.

2AI+ 6HCl -> 3H2 + 2AlCl3

Reaction type: Single Replacement

8.

IDK

Reaction type: Double Replacement?

Explanation:

8 0
2 years ago
uyty7trrhgr sjkrvhvdvhv idlhasg iaiosg sidrug iowyhg eiroygiyega riyh aeoirgv aeyg reioaaioeyr goirfoiyer goiag oare5iphq vouptr
Vilka [71]

Answer:

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Explanation:

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6 0
3 years ago
33. At the right of a chemical equation are
Bas_tet [7]

Answer:

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4 0
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