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NeX [460]
3 years ago
6

Methane (CH4) reacts with excess oxygen gas (O2) to produce carbon dioxide (CO2) and water (H2O). What is the percent yield of c

arbon dioxide if the actual yield is 29.8 grams and the theoretical yield is 0.814 moles?
Chemistry
1 answer:
kotegsom [21]3 years ago
6 0
I'm pretty sure that it's either 83.2% or 91.4%
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Which statement is always true about a reversible chemical reaction?
Alecsey [184]
<h2>Answer:</h2>

Option (B):

The products can form reactants, and the reactants can form products.

<h3>Explanation:</h3><h3>Reversible reaction</h3>

A reversible reaction is a reaction where the reactants form products, which react together to give the reactants back.

aA + bB ⇄ cC + dD

A and B can react to form C and D or, in the reverse reaction, C and D can react to form A and B.

Other options are wrong because off:

(A) Concentration changes with time equilibrium concentration and higher product concentration is also possible.

(C) They may be constant.

(D) Concentration changes with time equilibrium concentration and higher reactant concentration is also possible.

7 0
3 years ago
Which one of the following pairs of separation techniques will BOTH separate salt from a mixture of salt and water?
Natali5045456 [20]

Answer:

What are the options and i dont know what the options are but if one of them is distilation im 99.9% sure that is the answer.

Explanation:

Be sure to friend me and mark me as braniliest if im correct!

6 0
3 years ago
For each element, predict where the "jump " occurs for successive ionization energies. (For example, does the jump occur between
vichka [17]

Answer:

A jump occurs when a core electron is removed.

Explanation:

A jump in ionization energy occurs when a core electron is removed. A large jump in the ionization energy easily be seen from the electronic configuration of an element.

For Beryllium, the electronic configuration of is 1s2 2s2.

There are two valence electrons in the outermost shell hence the ionization energy data for beryllium will show a sudden jump or increase in going from the second to the third ionization energy owing to the removal of a core electron

The electronic configuration for Nitrogen is 1s2 2s2 2p3. Five valence electrons are found in the outermost shell so the ionization energy data for nitrogen will show a sudden jump or increase in going from the fifth to sixth ionization energy because of the removal of a core electron

The electronic configuration of oxygen is 1s2 2s2 2p4. There are six valence electrons hence ionization energy for oxygen atom will show a sudden jump or increase in going from the sixth to the seventh ionization energy because of the removal of a core electron

The electronic configuration of Lithium is 1s2 2s1

There is one valence electron in its outermost shell so its ionization energy data will show a sudden jump or increase in going from the first to the second ionization energy because of the removal of a core electron.

8 0
4 years ago
The danger from radon gas would most likely be greatest in:.
Semmy [17]

The danger from radon gas would most likely be greatest in well-insulated homes. It is a toxic gas.

<h3>What is radon gas?</h3>

Radon is a naturally radioactive gas generated from different elements such as uranium or radium.

Radon is generated when these radioactive materials naturally decompose in the soils and/or rocks.

Radon is highly toxic and therefore this gas must be avoided to maintain healthy conditions in a home.

Learn more about the radon gas here:

brainly.com/question/1121893

5 0
2 years ago
Calculate the mole fraction of cai2 in an aqueous solution prepared by dissolving 0.400 moles of cai2 in 850.0 g of water.
alukav5142 [94]
1) Formulas:

a) mole fraction of component 1, X1

X1 =  number of moles of compoent 1 / total number of moles

b) Molar mass = number grams / number of moles => number of moles =  number of grams / molar mass


2) Application

Number of moles of CaI2 = 0.400

Molar mass of water = 18.0 g/mol

Number of moles of water: 850.0 g / 18.0 g/mol = 47.22 mol

Total number of moles = 0.400 + 47.22 =47.62

Molar fraction of CaI2 = 0.400 / 47.62 = 0.00840
7 0
3 years ago
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