IN THE GIVEN CARTON 10 EGGS ARE OKAY AND 2 ROTTEN .WE ARE REQUIRED TO SELECT 4 OKAY EGGS.THIS CAN BE DONE IN 10C4 WAYS=210 WAYS
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Answer: 16</h3>
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Explanation:
Equate s(t(x)) and s(1) to find that t(x) = 1 must be the case.
Let's find what x must be.
t(x) = 3x-8
1 = 3x-8
1+8 = 3x
9 = 3x
3x = 9
x = 9/3
x = 3
So plugging x = 3 into t(x) gets us t(x) = 1
In other words, t(3) = 1
So that tells us s(t(3)) = s(1)
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Let's plug x = 3 into the s(t(x)) equation
s(t(x)) = x^2 + 3x - 2
s(t(3)) = (3)^2 + 3(3) - 2
s(1) = 9 + 3(3) - 2
s(1) = 9 + 9 - 2
s(1) = 18 - 2
s(1) = 16
Answer:
x = 8.64
x = - 7.64
Both to 2 d.p
Step-by-step explanation:
Firstly, - 8 both side - cancels the +8 & get the surd to equal x - 8
Then, square root both side, to get:
x-2= x^2 - 64
+ 2 both side
x = x^2 - 66
-x
0= x^2 - 66 - x
x^2 - x - 66 = 0
general equation for quadratic is ax^2 + bx + c
Now, we can find the value of a, b, c using x^2 - x - 66 = 0
a=1
b= - 1
c= - 66
Now use quadratic formula
x = -b±√(b²-4ac))/(2a
= --1 + √ - 1 x - 1 - 4x1x-66 / 2x1
= 8.639.....
Now repeat with - b - & not - b +
x = -b±√(b²-4ac))/(2a
= --1 - √ - 1 x - 1 - 4x1x-66 / 2x1
= - 7.639.......
Hi, hope this helps, so the sum is 10+12+(-27)+(-9)+10
Then -10 + 12 - 27 - 9 + 10= -54 + 20= 26
So the answer is -26
