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Oksi-84 [34.3K]
3 years ago
9

Nick started 60% of his team's football games this year he started in a total of 12 games

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
3 0

Answer:

20

Step-by-step explanation:

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Is -1 1/2 rational?
stepan [7]

Answer:

yes

Step-by-step explanation:

-1 1/2 = -3/2

A rational number is a number that can be written as a fraction of integers.

-1 1/2 is the same as -3/2.

-3 and 2 are integers, so -3/2 is a fraction of integers.

Answer: yes

8 0
3 years ago
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Find the value of x (round to the nearest tenths)<br> 3x<br> 4x
Schach [20]

Answer:

Sorry nakalimutan ko

Step-by-step explanation:

Di koma search

5 0
2 years ago
The first quartile in a box-and-whisker plot would be located on what number?
astraxan [27]

Answer:

24.5

Step-by-step explanation:

When you round it you get 25. (sorry if im wrong) :(

4 0
3 years ago
Bacteria of species A and species B are kept in a single environment, where they are fed two nutrients. Each day the environment
DiKsa [7]

Answer:

We require 4,550 of species A and 1,460 of species B that can coexist in the environment so that all the nutrients are consumed each day

Step-by-step explanation:

Let n₁ be the population of A required and n₂ be the population of B required.

Now we require 2 units of the first nutrient for species A and one unit of the first nutrient for species B. The total nutrients required by species A is 2n₁ and that by species B is 1n₂ = n₂. So, the total nutrients required by both species A and B is 2n₁ + n₂. Since this equals the quantity of the first nutrient which is 10,560, then  2n₁ + n₂ = 10,560 (1)

Now we require 5 units of the second nutrient for species A and 6 units of the second nutrient for species B. The total nutrients required by species A is 5n₁ and that by species B is 6n₂. So, the total nutrients required by both species A and B is 5n₁ + 6n₂. Since this equals the quantity of the first nutrient which is 31,510, then  5n₁ + 6n₂ = 31,510 (2).

So, we have two simultaneous equations which we would solve to find the populations of A and B which satisfy both equations.

2n₁ + n₂ = 10,560  (1)

5n₁ + 6n₂ = 31,510 (2)

From (1) n₂ = 10,560 - 2n₁ (3)

Substituting equation (3) into (2), we have

5n₁ + 6(10,560 - 2n₁) = 31,510

expanding the brackets, we have

5n₁ + 63,360 - 12n₁ = 31,510

collecting like terms, we have

5n₁ - 12n₁ = 31,510 - 63,360

simplifying, we have

- 7n₁ = -31,850

dividing both sides by -7, we have

n₁ = -31,850/-7

n₁ = 4,550

Substituting n₁ = 4,550 into (3), we have

n₂ = 10,560 - 2(4,550)

n₂ = 10,560 - 9,100

n₂ = 1,460

So, we require 4,550 of species A and 1,460 of species B that can coexist in the environment so that all the nutrients are consumed each day

3 0
2 years ago
400 thousands + 600 thousands in standard form​
ruslelena [56]

Answer: 1 million

Step-by-step explanation:

4 0
3 years ago
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