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2 years ago

Question in picture, thankyou

Mathematics

2 answers:

Elza [17]2 years ago

6 0

Answer:

33% of 100% of men

Step-by-step explanation:

Add 50 + 19 + 24 = 93

(amount of men doing anything other than lifting) 93÷140= 0.664 (about 66%)

(amount of men lifting) 47÷140= 0.335 (about 33-34%)

So 33% out of 100% of men would lift.

geniusboy [140]2 years ago

3 0

Answer:

19.82%

Step-by-step explanation:

Add all members that want weight lifting

47 + 21 + 14 + 29 = 111

111 / total members

111 / 560 = 0.1982

0.1982 * 100% = 19.82%

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I need help with #39-42, please explain.

shusha [124]

For question 39 & 40, we need to use the below equation to complete the sentence

$l=m\sqrt{n}$

Question 39:

When ' n ' increase, the $\sqrt{n}$ will also increase and that multiplied with constant ' m ', the l will also increase.

Solution for question 39:

As $n$ increases and $m$ stays constant , $l$ increases

-------

Question 40:

Solving the equation for m, we get

$l = m\sqrt{n} \\ \\ m=\frac{l}{\sqrt{n}}$

When ' l ' increases, the numerator increase, the denominator stays constant because 'n' stays constant, for this condition, the fraction increases.

Solution for question 40:

As $l$ increase and $n$ stays constant, $m$ increases

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For question 41 & 42, we need to use the below equation to complete the sentence

$r=s^2/t^2$

Question 41:

When $s$ is triped, the equation will be...

$r=(3s)^2/t^2=\frac{3^{2}s^{2}}{t^2} =9s^2/t^2$

Solution for question 41:

If $s$ is tripled and $t$ stays constant, $r$ is multiplied by 9

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Question 42:

When t is doubled, the equation will be...

$r=s^2/(2t)^2=\frac{s^2}{2^2 \cdot t^2}=\frac{s^2}{4t^2}\\ \\ r=0.25s^2/t^2 \; \; (or) \; \; \frac{1}{4} \cdot \frac{s^2}{t^2}$

Solution for 42:

If $t$ doubled and $s$ stays constant, $r$ is multiplied by 1/4 or 0.25

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3 years ago

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prisoha [69]

I = interest/simple interest

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3 years ago

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3 years ago

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Papessa [141]

Answer:

-5x + y = -27

Step-by-step explanation:

Equation: y+8 = -5(x+3)

Standard form is (ax + by = c)

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luda_lava [24]

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Question in picture, thankyou ​

Question in picture, thankyou