Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:
y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5
To try to discard one of them, let us use the vertex, which is at x = -2.
With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.
Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.
Then, the answer is 2x^2 + 8x -5
Answer:
C
Step-by-step explanation:
Edge2021
Answer:
Hope this helps :)
Step-by-step explanation:
8(x - 2) = 2x + 8
y+9 = -2(y + 1)
value of x in 8(x - 2) = 2x + 8
x=4
substitue
y+9=−2(y+1)
value of y y+9=−2(y+1)
y= - 11/3 or 3.66...
x=4
y=4 (I rounded 3.66)
Step-by-step explanation:
2x = y-10
Rewrite as: 2x + 10 = y
Therefore:
2x+10 = y
2x +7 = 2y
Subtract the equations:
2x + 10 = y
- 2x + 7 = 2y
______________
3 = -y
Therefore y = -3
Substiture y = -3 into the second equation:
2x + 7 = 2(-3)
2x + 7 = -6
2x = -13
x= -6.5
Answer : (-6.5, -3)
Answer:
160,170 and 240,250
Step-by-step explanation:
sorry if wrong
