To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer:
the perimeter is 18
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
Y E S : )
Step-by-step explanation:
(3m^2-p)(3m-p^2)
You factor out the 3m^2 and p from the combined like terms and then group those into a factor and group the two identical factors together and (3m^2-p)(3m-p^2) is your answer.
