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3 years ago

Find the values of x and y.

Mathematics

1 answer:

lara31 [8.8K]3 years ago

5 0

Answer:

x=90 y=43

Step-by-step explanation:

by looking at the diagram you can infer that the triangles are similar, this means that angle B and angle C both equal 47 degrees. you can also infer by the straight angle underneath both angles the both angle Ds add up to 180 and because they are similar triangles that means they are right angles giving you the x value, 90 degrees. after this you know that a triangle adds up to equal 180 degrees meaning if you add 90 and 47 together and subtract that from 180 you get the value of y, 43.

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A bag contains 2 red marbles, 7 blue marbles and 5 green marbles. If two marbles are drawn out of the bag, what is the exact pro

vivado [14]

Answer:

0.25 or 25%.

Step-by-step explanation:

2 Red + 3 Blue + 7 Green = 12 Total Marbles.

You have 3 blue marbles out of the total marbles, so 3/12, then simplify it. 3/12 = 1/4. This gives you 0.25, or 25%.

The probability of drawing a blue marble is 0.25 or 25%

4 0

2 years ago

Can someone please help me this this??

Brrunno [24]

Answers:

bio = 258

sociology = 169

============================================================

Work Shown:

x = number of bio textbooks

y = number of sociology textbooks

x+y = 427 books sold total

y = x-89 since 89 less sociology textbooks were sold compared to bio

Apply substitution to get the following

x+y = 427

x+x-89 = 427 ... replace y with x-89

2x-89 = 427

2x = 427+89

2x = 516

x = 516/2

x = 258 bio textbooks were sold

y = x-89

y = 258-89

y = 169 sociology textbooks were sold

5 0

1 year ago

Determine as a linear relation in x, y, z the plane given by the vector function F(u, v) = a + u b + v c when a = 2 i − 2 j + k,

Ostrovityanka [42]

Answer:

2x - y - 3z = 0

Step-by-step explanation:

Since the set

{i, j} = {(1,0), (0,1)}

is a base in $\mathbb{R}^2$

and F is linear, then

{F(1,0), F(0,1)}

would be a base of the plane generated by F.

F(1,0) = a+b = (2i-2j+k)+(i+2j+k) = 3i+2k

F(0,1) = a+c = (2i-2j+k)+(2i+j+2k) = 4i-j+3k

Now, we just have to find the equation of the plane that contains the vectors 3i+2k and 4i-j+3k

We need a normal vector which is the cross product of 3i+2k and 4i-j+3k

(3i+2k)X(4i-j+3k) = 2i-j-3k

The equation of the plane whose normal vector is 2i-j-3k and contains the point (3,0,2) (the end of the vector F(1,0)) is given by

2(x-3) -1(y-0) -3(z-2) = 0

or what is the same

2x - y - 3z = 0

3 0

3 years ago

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Sedbober [7]

Answer:

this answer is. _48 am I right

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2 years ago

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IRISSAK [1]

Answer:

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Step-by-step explanation:

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3 years ago